I am using S12zvl 128ms, It is taking 5.04ms to erase one sector (4 Bytes) on EEPROM.
If I want to erase 64 bytes, how long will it take me?
Is it 64/4*5ms?
Is there another way to speed things up?
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Hello @jingfang,
There is only the specification that can be found in the RM, Table E-2.
The execution time depends on f_NVMOP and f_NVMBUS (footnotes 1-4).
4.80ms is then the minimum for 4B sector.
And ~((64 / 4) * 4.8ms) for 64 bytes.
BR, Daniel
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