Hi,
can you please give me an example of how to calculate the maximum supply current? i didn't understand it from the picture below
NVCC_EMC(max curr)= 42*C*3.3*0.5F= 69.3CF
please help me estimate C and F
Solved! Go to Solution.
Hi @sapirbuz ,
No, C couldn't be 4.9uF. It's impossible to push 42 4.9uF cap to 60M. Please refer to this post.
https://community.nxp.com/t5/i-MX-Processors/Question-i-MX6Solo-Max-supply-current/m-p/416445
Regards,
Jing
View solution in original post
C is the whole capacitor load on the pin group. You can add them all according to your design.
F is signal frequency. For example, if the pin group is for SDRAM, then take the SDRAM working frequency.
This bank consists 42 pins, what freq should I choose?
what is the maximum freq?
This formula can help you to estimate maximum power consumption. It could not be very accurate. So, just use the highest frequency signal. For example, if the highest frequency signal in this group is a SPI, you can use the SPI bus frequency.
https://community.nxp.com/t5/i-MX-RT/RT1170-Max-Supply-Current-Calculation/td-p/1359582
F= 60MHz (QSPI)
C= 4.9uF (according to eval board)
NVCC_EMC(max curr)= 42*C*3.3*0.5F= 69.3CF= 20374.2A?
what did i miss?
only for QSPI pins:
4*4.9u*3.3*0.5*60M= 1940A
it doesn't make sense
thank you
