Can anyone tell me what is the size of K70 RAM. I got confused by 2 different explanation.
From the datasheet, it is said 128KB as pasted below:
Another way is from icf file, from the file, it seems that it is 64KB.
| MK70FN1M0_RAM.icf |
|---|
/*-Memory Regions-*/ define symbol __ICFEDIT_region_ROM_start__ = 0x00000000; define symbol __ICFEDIT_region_ROM_end__ = 0x0007FFFF; define symbol __ICFEDIT_region_RAM_start__ = 0x20000000; define symbol __ICFEDIT_region_RAM_end__ = 0x2000FFFF; /*-Sizes-*/ define symbol __ICFEDIT_size_cstack__ = 0x4000; define symbol __ICFEDIT_size_heap__ = 0x4000; /**** End of ICF editor section. ###ICF###*/ |
So what is the real size?
Presently I'm usng the MK70FX512VMJ12.
Jeff
All K70s have 128k - to be absolutely sure, always check the orderable parts in the respective user's manual:
I don't know where you got the linker script file from but it is only allocating the RAM_U (0x20000000..0x2000ffff) and not RAM_L (0x1fff0000..0x1fffffff).
Generally
define symbol __ICFEDIT_region_RAM_start__ = 0x1fff0000;
define symbol __ICFEDIT_region_RAM_end__ = 0x2000FFFF;
is correct but it may be that only half of the RAM is being used due to worries about the fact that there is a restriction when accessing data in both RAM_L and RAM_U (burst accesses can't occur across the 0x20000000) but this is a very specific case and usually one can just use it as if it were a single block of memory.
Regards
Mark
Kinetis: µTasker Kinetis support
K70: µTasker Kinetis TWR-K70F120M support / µTasker EMCRAFT K70F120M support
For the complete "out-of-the-box" Kinetis experience and faster time to market
Jeff
All K70s have 128k - to be absolutely sure, always check the orderable parts in the respective user's manual:
I don't know where you got the linker script file from but it is only allocating the RAM_U (0x20000000..0x2000ffff) and not RAM_L (0x1fff0000..0x1fffffff).
Generally
define symbol __ICFEDIT_region_RAM_start__ = 0x1fff0000;
define symbol __ICFEDIT_region_RAM_end__ = 0x2000FFFF;
is correct but it may be that only half of the RAM is being used due to worries about the fact that there is a restriction when accessing data in both RAM_L and RAM_U (burst accesses can't occur across the 0x20000000) but this is a very specific case and usually one can just use it as if it were a single block of memory.
Regards
Mark
Kinetis: µTasker Kinetis support
K70: µTasker Kinetis TWR-K70F120M support / µTasker EMCRAFT K70F120M support
For the complete "out-of-the-box" Kinetis experience and faster time to market
