I want to replace pf0100 with pf0200 in i.MX6DL boards.
Are they pin-to-pin compatible or need another work for PCB?
Solved! Go to Solution.
Hi JHY
MMPF0200 is MMPF0100 (pin compatible) minus SW1C and SW4, SW2=1.5A.
Since SW1C is absent in the PF0200, both VDDCORE and VDDSOC
are powered by the SW1AB regulator. Peripherals connected to the SW4
regulator in the original reference design can be powered by the SW2 regulator
when using the PF0200.
Best regards
igor
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Hi JHY
MMPF0200 is MMPF0100 (pin compatible) minus SW1C and SW4, SW2=1.5A.
Since SW1C is absent in the PF0200, both VDDCORE and VDDSOC
are powered by the SW1AB regulator. Peripherals connected to the SW4
regulator in the original reference design can be powered by the SW2 regulator
when using the PF0200.
Best regards
igor
-----------------------------------------------------------------------------------------------------------------------
Note: If this post answers your question, please click the Correct Answer button. Thank you!
-----------------------------------------------------------------------------------------------------------------------