Voltage Drop on GPIO

[hamid_abrishami]

Hi every one!
we use S32K148 in our product. in data sheet it seems that said if we sink or source 5mA on typical GPIO or IohGPIO-HD_DSE_0 we have 0.8V drop on out put means: VoH(minimum) = 5 - 0.8 = 4.2 and VoL(Maximum) = 0 + 0.8 = 0.8
I want to know what happen if we source below this current for instance 4mA.
Dose we have any curve for illustrate the relation between the source current VS drop Voltage on output. 
what about GPIO-fast.

Thanks 

 

[hamid_abrishami]

thanks 
And what happen if we source current more than 5mA. Does Vout drop more than 0.8V ?  

[Robin_Shen]

As the source current becomes larger, the voltage drop will also become larger.

[Robin_Shen]

I want to know what happen if we source below this current for instance 4mA.

Then the actual output VoH is higher, that is, the voltage drop will not be as much as 0.8v.

Dose we have any curve for illustrate the relation between the source current VS drop Voltage on output. 

Sorry, I didn't find this kind of curve on the public information.

The following are the GPIO-FAST pins on the S32K148 chip:

Best Regards,
Robin
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