Need Clarification in EEPROM Functionality why FTFC->FCCOB[3] using as FCCOB0?
06-09-2020
04:50 AM
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shivamshankarg
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Hello Team,
I was reading the document "AN11983 Using the S32K1xx EEPROM Functionality" for memory partition.
What I found in page no. 7:-
FTFC-> FCCOB [3] = 0x80; /* FCCOB0: Selects the PGMPART command */
FTFC-> FCCOB [2] = 0x00; /* FCCOB1: No CSEc operation */
FTFC-> FCCOB [1] = 0x00; /* FCCOB2: No CSEc operation */
FTFC-> FCCOB [0] = 0x00; /* FCCOB3: FlexRAM loaded with valid EEPROM during reset sequence */
Just want to ask,
why FCCOB0 will be modified using FTFC->FCCOB[3] not FTFC->FCCOB[0]?
means why all the index of FCCOB is not correspond with the same number like FCCOB0 to FTFC-> FCCOB [0] and FTFC-> FCCOB [1] to FCCOB1 like that?
Kindly assist?
2 Replies
06-11-2020
02:03 AM
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NXP TechSupport
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Hello ,
The registers are offset like this:
Regards,
Daniel
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06-11-2020
01:15 AM
1,642 Views

shivamshankarg
Contributor III
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Kindly assist.
