Why does a single step execution with S32 Debug Pro simulation enter this timer interrupt

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Why does a single step execution with S32 Debug Pro simulation enter this timer interrupt

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RanDong
Contributor I

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petervlna
NXP TechSupport
NXP TechSupport

Hello,

Just a blindshot. Your timer is running in debug mode. So if you do single steps, then counter will run out and set the timeout flag.

So if you take next step it will jump into ISR if that has the actual highest priority.

Check if you can enable debug mode on GPT.

Best regards,

Peter

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