ADC Raw Values read from NTC and Current Value measured via MM9Z1J638 and

[kadiruzun]

Hello All,

I am studying on MM9Z1J638 and trying to understand its basics for a while. I have one question regarding to ADC values I obtained from current and temperature channels. I see 24 bit current measurement result and 16 bit raw value related to temperature. However, I do not understand what these values mean. I know that the value I read from temperature channel is dependent on the NTC I used, but is this value a voltage value, or is it something other? How I can convert, for instance the value I see from current channel to something I can understand in terms of Amps?

The demo code makes some conversions however I did not quite get how it gets temperature result form Raw ADC value. It also converts current to miliamps but I am not sure if the result I get is miliamps because what I watched on CodeWarrior is a number in Billion levels or so on. I am not sure if 12billion miliamp is something logical or not.

I am looking forward to see your response about this issue.

Thanks in advance

[iggi]

Hi Kadir,

I suppose that the current reading value represents the voltage which should be converted by following equation:

Voltage = ADC_reading * (REFERENCE_VOLTAGE) / ADC_resolution

And then, that voltage divided by shunt resistor value (100uOhm) to get actual current value in Amps.

 The sigma-delta ADC resolution is 16-bit. Not sure if the reference voltage is 5V

 I suppose we should consider the PGA gain too in this equation.

The big number as current reading you get is maybe because you are measuring negative current.

Regards,

iggi

[kadiruzun]

Hello Iggi,

Thank you for your response. I still have questions regarding to tthe same problem, if you let me I would like to ask one more thing. The following piece of code is taken from example code.

u32CsenseValue = (u32) B_ACQ_CURR0; // read 24bit result (two's complement 24 bit integer)

u32CsenseValue |= (u32)B_ACQ_CURR1<<16;

This shows that ADC value is kept as 32 bits rather than 24 bits which is expressed in datasheet of mm9z1j638. I think that the value in the order of 10billions is due t.o this reason. If you have more comment on this situation (its being stored as 32bit value), I am looking forward to hear.

Thanks,

Kadir

[iggi]

The result is 24bit and needs to be sign-extended to 32bit.

e.g.:

       s32AcqCurr = (s32)B_ACQ_CURR1<<16 | (s32)B_ACQ_CURR0;

       s32Current = S24SignExtend(AcqCurr);                                 // sign extend and sum up

The following macros are used:

#define S24EXTENT                 (0xFF000000UL)                        //!< macro to extend negative s24 to s32                                                                                                                          

//#define S24SignExtend(s24)     ((s24)&BIT(23))? (s24)+S24EXTENT : (s24)// works with OR and ADD                                                                                          

#define S24SignExtend(s24)    ((s24)&BIT(23))? (s24)|S24EXTENT : (s24)  //!< macro to sign extend s24 bit values to s32

The resolution of the B_ACQ_CURR is 0.1uV (if shunt selection is default = 100uOhm).

In this case if you use a 100uOhm shunt the resolution is one 1mA.

Regards,

iggi

[kadiruzun]

Hi again Iggi,

Do I need to include 32bit result to convert ADC to ampere or the last 24 bit enough in this formula Voltage = ADC_reading * (REFERENCE_VOLTAGE) / ADC_resolution?