2381525_en-US

Yes

S32k328 HSE DomainID

Hello, NXP Technical Team

I am writing to inquire about accurately verifying the S32k328 Domain ID.

I am currently using an S32k328 board and HSE Firmware.

- Setup Environment:

I am using the HSE Firmware image s32k358_hse_fw_1.14.0_2.40.0_pb230807.bin.

I am currently in a multi-core state and using RM module(only use XRDC).

- Question:

In the HSE FW RM, the S32k328 Domain ID is set to 2 as shown in the attachment.

However, in the S32k328 Block Diagram within the S32k3xx RM, the HSE is set to MDAC3, and the DID (Domain ID) of MDAC3 is output as 3.

(1) Register Verification Code:

uint32_t mda[8];

mda[0] = IP_XRDC->MDA_W0_0_DFMT0;

mda[1] = IP_XRDC->MDA_W0_1_DFMT1;

mda[2] = IP_XRDC->MDA_W0_2_DFMT1;

mda[3] = IP_XRDC->MDA_W0_3_DFMT0;

mda[4] = IP_XRDC->MDA_W0_4_DFMT0;

mda[5] = IP_XRDC->MDA_W0_5_DFMT1;

mda[6] = IP_XRDC->MDA_W0_6_DFMT0;

mda[7] = IP_XRDC->MDA_W0_7_DFMT1;

UART_Print("--- MDA Locks ---\n");

for (uint32_t i = 0; i < 8; i++)

{

uint32_t vld = (mda[i] >> 31) & 1U;

uint32_t lk1 = (mda[i] >> 30) & 1U;

uint32_t did = mda[i] & 0x3U;

UART_Print("MDA%lu=0x%lx VLD=%lu DID=%lu LK1=%lu %s\n",(unsigned long)i, (unsigned long)mda[i],(unsigned long)vld, (unsigned long)did, (unsigned long)lk1,lk1 ? "(LOCKED)" : "");

}

(2) Register Value:

MDA0=0x80000000 VLD=1 DID=0 LK1=0
MDA1=0x20000000 VLD=0 DID=0 LK1=0
MDA2=0x20000000 VLD=0 DID=0 LK1=0
MDA3=0xc0000003 VLD=1 DID=3 LK1=1 (LOCKED)
MDA4=0x80000001 VLD=1 DID=1 LK1=0
MDA5=0x20000000 VLD=0 DID=0 LK1=0

What is the correct S32k328 Domain ID?

Re: S32k328 HSE DomainID

Hi @dpsdprtmvl

S32K328 has four domains 0-3 and HSE is always assigned to highest available domain – to domain 3 in this case:

This is hardwired and it cannot be changed.

The Table 136 is little bit confusing because it shows only main derivatives, not all sub-derivatives. That means:

S32K32x in the second row stands for S32K322 and S32K324.

S32K35x in the third row stands for S32K358, S32K356, S32K348, S32K338, S32K328 and S32K37x and S32K39x derivatives.

Regards,

Lukas