I am using MQX 3.8 and TWRK60N512. The tick rate is set to 5ms in the mQX. I want to know what happens when the I use _time_delay(1) as the task tick is 5ms.
So what is the minimum delay I can use with _time_delay() when the tick rate is 5ms ?
Minimum resolution is 5ms if it's set to 5ms (BSP ALARM FREQ = 200). When you pass number below 5 as an argument in this case, you'll get the minimum resolution.
Minimum resolution is 5ms if it's set to 5ms (BSP ALARM FREQ = 200). When you pass number below 5 as an argument in this case, you'll get the minimum resolution.
Thnaks for your reply. So it might be that we get lower than 5ms depending on when we are calling _time_delay(1) i.e. if we call _time_delay(1) just before the next tick then it will occur when the next tick happens.
Also what if we give anything above 5 and below 10 ? Does it work in similar way (i.e. it only delays till the next tick).
It should always delay for AT LEAST as long as you specify in _time_delay, it may well be longer, depending on the system tick, other tasks running, etc.
