Place own binary code in program memory TWRK60N512

[Thommi_Tulpe]

Hello,

i have to place my own assembled binary code into the

program memory (RAM) e. g. at the address 0x70000.

My code is very small only a few 32 bit arm instructions.

At the end of the code I jump back to the main programm.

(mov pc, r14)

How can I place my binary code at address 0x70000 in RAM.

I will place my 32 bit instructions in a array.  The first member of the array must placed at 0x70000,

the second at 0x70004, and so on.

I using the CodeWarrior 10.1

Best Regards

Thomas

[mjbcswitzerland]

Thomas

Presumably you will need to have the small code stored in Flash memory and copy it to RAM when the processor starts.

I assume that simply memcpy((void *)0x70000, code_array, sizeof(code_array)); will be adequate, where code_array[] is your code in flash.

Regards

Mark

[Thommi_Tulpe]

Hello Marc,

i made an mistake.

I don't want to place my binary code at 0x70000, because its Flash.

I want to place my binary code in RAM Memory. (eg. 0x1fff000-0x1fff800)

I use the default lcf-file.(MK60N512VMD100_flash.lcf)

Do I have to change the Linker Command File ?

I want to have my main code in flash and my selfmade binary code in RAM.

This is what I want:

code_array[0] = 0xE3A00000;      // MOV r0, #0
code_array[1] = 0xE2800001;      // ADD r0, #1
code_array[2] = 0xE340000A;     // CMP r0, #10 
code_array[3] = 0x1AFFFFFE;
code_array[4] = 0xE1AEF000;   // MOV pc, r14 (return to flash-program)

        
 memcpy((void *)0x1FFF0000, code_array, sizeof(code_array));   // copy binary code in RAM

asm{
        MOV r14, pc
        MOV pc, #0x1FFF0000        
    };       //jump to binary code in RAM

Thanks