Support BT1120 progressive mode in Mx6Q

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Support BT1120 progressive mode in Mx6Q

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shaojun_wang
NXP Employee
NXP Employee

The HDMI receiver verified with Mx6Q is SiI9135.

 

Hardware connection

According "Camera Input Signal Cross Reference, Format, and Bits Per Cycle" in Mx6Q Datasheet, the pin mapping is CSIx_DAT2 ~ CSIx_DAT9 <----> C[0] ~ C[7], CSIx_DAT12 ~ CSIx_DAT19 <----> Y[0] ~ Y[7].

In "YC 4:2:2 Formats with Embedded Syncs" of SiI9135 datasheet, the pin mapping is Q16 ~ Q23 <----> Y0 ~ Y7,  Q28 ~ Q35 <----> Cb0 ~ Cb7.

So Q28 ~ Q35 of SiI9135 should be connected to CSIx_DAT2 ~ CSIx_DAT9 of Mx6Q, Q16 ~ Q22 are connected to CSIx_DAT12 ~ CSIx_DAT19 of Mx6Q.

 

Kernel Patch

sii9135.patch is the kernel patch to support BT1120 progressive mode.

Original Attachment has been moved to: sii9135.patch.txt.zip

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isaacnickaein
Contributor III

This patch seems to be for Kernel 3.0.35 BSP. Is this patch required for Kernel 3.10.17/53 BSP too?

I am looking for a way to capture BT1120 192x1080 Interlaced video using parallel CSI on Kernel 3.10, but I cannot find any resources/patches for this.

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wuchirk
Contributor II

Hi Isaac,

Did you fixe your problem?

I am also looking BT1120 interlace on iMX6Q, but I have dequeue timeout issue.

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ottob
Contributor IV

This works well for us capturing 720P and 1080P. It does not appear that the state of the 4 unused pins make any difference

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nealbush
Contributor I

hi Shaojun

I followed the patch and try to get bt1120 progressive data .  but i can't  get the data from CSI0 .Are you sure other alternate  is not needed?

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kyu-myounglee
Contributor I

Question about 16bit BT.1120 interface pin connection.

I recognized that Table 68(Camera Input Signal Cross Reference, Format, and Bits Per Cycle) in the datasheet indicates not "-" but "0" to the 4 unused data pins(CSIx_DATA00/01/10/11) for 16bit BT.1120.

It is understood that those pins should be pulled down to logic 0.

Is it really necessary to tie those pins to ground in the circuit ?

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brunolain
Contributor I

Hi, did you understand this question?

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