Hi
I was following i.MX Linux® User's Guide and implemented the disc encryption.
./caam-keygen create randomkey ecb -s 16 is used for creating the key
dmsetup -v create encrypted --table "0 $(blockdev --getsz /dev/loop0) crypt capi:tk(cbc(aes))-
plain :36:logon:logkey: 0 /dev/loop0 0 1 sector_size:512" is used for creating the new device mapper. and 36:logon:logkey: is confusing me.
I have the following doubt:
How to ensure the keysize of the algorithm
1. I ran the following command and I got the following output
dmsetup table --showkey encrypted
0 65536 crypt capi:tk(cbc(aes))-plain :36:logon:logkey: 0 7:0 0
what is this 36
2. If I want to implement AES 256 what changes I have to make in the the above code.
Thanks,
Rahul B
