Hi
I am using Qn9080 for my application. As per data sheet i connected below circuit in my schematic.
pavan252_0-1606043517403.png
To enable internal DC-DC i connected as shown above but i am betting 0.6V after L1 inductor instead of 1.3V. Because of this low voltage i am unable to program my controller. VCC i am connecting as 3V.
By default the internal DC-DC converter will be enabled so it will convert high voltage of VCC to low voltage i.e 1.3V. But after assembling my PCB i am trying to program first time and the voltage at IDC is showing 3V but after L1 it's 0.6V. I am using the same values of inductors recommended in eval board.
Please support.
Regards
Pavan.