S32K46 CAN 2.0 Sample point

[玉敏111田]

I have not found the classical CAN (not FD CAN) sample point in S32K-RM.

So which method should be used to calculate classical CAN sample point below?

1).（1+TSEG1）/(1+TSEG1+TSEG2)

2. （1+TSEG1+PROP_SEG）/(1+TSEG1+PROP_SEG+TSEG2)

[Robin_Shen]

Hi 玉敏111 田,

Please refer the Figure 55-7. Segments within the bit time (example using CTRL1 bit timing variables for Classical CAN format) of S32K-RM.

（1+TSEG1）/(1+TSEG1+TSEG2)

（1+PROPSEG+PSEG1+2）/(1+PROPSEG+PSEG1+2 + PSEG2+1)

By the way, the Processor Expert will calculate sample point automatically.

Best Regards,

Robin

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[玉敏111田]

[Robin_Shen]

Sorry

I didn't understand what you mean.

For example:

.propSeg = 7,
.phaseSeg1 = 4,
.phaseSeg2 = 1,

sample point =（1+Time Segment 1）/(1+Time Segment 1+Time Segment 2)=（1+PROPSEG+PSEG1+2）/(1+PROPSEG+PSEG1+2 + PSEG2+1) = (1+7+4+2)/  (1+7+4+2  +1+1)=87.5%

Best Regards,

Robin

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[玉敏111田]

Hi Robin,

Thanks for your reply.

When I calculated the sample point ,I found that the PSEG1 in Figure 55-7 was the same with Phase Buffer Segment 1 in S32K-RM  rather than PSEG1 in S32K-RM.