Hi @Caleb1,
Out of the system reset, both regulators, the one with the internal ballast transistor and the one with the external ballast PNP are enabled.
danielmartynek_0-1692112469928.png
The external regulator has a slightly higher regulating point (5V) than the internal regulator (4.95V).
That means that the external regulator tries to regulate the VDDX voltage higher and opens the PNP (BCTL voltage is slightly lower than VSUP)
danielmartynek_1-1692112545889.png
Once the SW writes EXTXON = 0, INTXON = 1, the external regulator is disabled, that means Vemitter (VSUP) = Vbase (BCTL).
For this reason, the BCTL pin must be left unconnected if the PNP is not used.
Regards,
Daniel