PN7160 big SWR

cancel
Showing results for 
Show  only  | Search instead for 
Did you mean: 

PN7160 big SWR

Jump to solution
5,563 Views
KLP
Contributor I

Hello.

I have a small issue with matching the antenna to the PN7160 circuit. Everything seems fine, but not completely. The system operates in a single-ended configuration with the DXW21BN2511N# balun, in the setup as shown below.

Piecuch_0-1726643700857.png

X1 and X2 are inductors LQW18CNR16J00D (S1P models). X3 is the S1P measured using a VNA together with the balun. The simulation shows correct component selection:

Piecuch_1-1726643747343.png

The measurement in the actual circuit is very similar:

Piecuch_2-1726643823881.png

 

However, the SWR measurement indicates that the circuit is not well compensated.

Piecuch_3-1726643874136.png

 

The simulation shows the same as well:

Piecuch_4-1726643913845.png

The system works and reads NFC cards, but sometimes it freezes, generating a continuous 13.56 MHz signal, which leads to overheating. Where could the problem lie?

 

Krzysztof

 

0 Kudos
Reply
1 Solution
5,523 Views
Tomas_Parizek
NXP Employee
NXP Employee

Cześć Krzysztof, 

I would say that the matching looks fine. You have almost exactly 20 Ohm. 

The reason why you see this VSWR is that you are using 50 Ohm impedance system for your measurement while the impedance of the circuit is matched to 20 Ohm. 

We don´t use the VSWR because the output impedance of the chip is not 50 Ohm. 

We rather use this approach :

Tomas_Parizek_0-1726729772921.png

And then the output power of the chip respectively its input current can be calculated as described here -> 

https://community.nxp.com/t5/NFC/PN7160-PN7161-DPC-Symmetric-Tuning-Values/m-p/1922063/thread-id/119...

 

About the overheating. Can you check the TXLDO input current (VDD(UP) pin) during the continuios 13.56 MHz ? This current shall not exceed 250 mA. 

 

BR

Tomas 

Customer Application Support Enginner 

View solution in original post

12 Replies
5,518 Views
KLP
Contributor I

Yes, I confirm. After changing the generator's impedance from 50Ω to 20Ω, the SWR now shows correctly.

KLP_0-1726733395012.png

 

KLP_1-1726733424742.png

KLP_2-1726733464958.png

I will try to measure the current, but it may take a while as this sometimes happens only after several hours of operation.

 

Krzysztof

0 Kudos
Reply
5,524 Views
Tomas_Parizek
NXP Employee
NXP Employee

Cześć Krzysztof, 

I would say that the matching looks fine. You have almost exactly 20 Ohm. 

The reason why you see this VSWR is that you are using 50 Ohm impedance system for your measurement while the impedance of the circuit is matched to 20 Ohm. 

We don´t use the VSWR because the output impedance of the chip is not 50 Ohm. 

We rather use this approach :

Tomas_Parizek_0-1726729772921.png

And then the output power of the chip respectively its input current can be calculated as described here -> 

https://community.nxp.com/t5/NFC/PN7160-PN7161-DPC-Symmetric-Tuning-Values/m-p/1922063/thread-id/119...

 

About the overheating. Can you check the TXLDO input current (VDD(UP) pin) during the continuios 13.56 MHz ? This current shall not exceed 250 mA. 

 

BR

Tomas 

Customer Application Support Enginner 

5,496 Views
KLP
Contributor I
Continuous current is 244 mA.
0 Kudos
Reply
5,392 Views
Tomas_Parizek
NXP Employee
NXP Employee

Hello, 

 

Thanks for your feedback ! As the limit is 250mA, you are already quite close. I would suggest to sligly increase the tuning impedance (from 20 Ohms to e.g. 23-25 Ohms) or decrease the TXLDO output voltage. 

This should decrease the continuous current to approx 230 mA. 

 

BR

 

Tomas 

5,383 Views
KLP
Contributor I
Are the calculations from the spreadsheet the same when using the antenna with a balun as in the version without the balun? I have significant discrepancies between the spreadsheet, the simulation, and the actual circuit.
0 Kudos
Reply
5,304 Views
Tomas_Parizek
NXP Employee
NXP Employee

Hello KLP, 

Are you refering to this Antenna calculation excel sheet? 

Tomas_Parizek_0-1727678092881.png

Or the TX driver current calculation I shared before ?

 

BR

Tomas 

5,238 Views
vyacheslavguzhv
NXP Employee
NXP Employee

hi Tomas,

 

Following your recomendations changes are made. However the issue still remains. Let me followup with more details. Please find below current customer's schematic. Kindly suggest what else can be modified.

vyacheslavguzhv_0-1728052297205.png

 

0 Kudos
Reply
5,278 Views
KLP
Contributor I
YES. The measured current is 244[mA] and the calculated current is approximately 180[mA].
0 Kudos
Reply
4,094 Views
KLP
Contributor I
"What values of imaginary resistance are safe for the circuit?"**
0 Kudos
Reply
4,064 Views
Tomas_Parizek
NXP Employee
NXP Employee

Hello @KLP , 

Ideally, if the antenna is properly tuned. We recomenend to have imaginary offset +-3 Ohms from real axis for best efficiency. E.g. If your target tuning should be 20 Ohm. Then It is acceptable to have it as 20+-3i Ohm

If you detune the antenna by a card or a different object, the impedance will change to e.g. (7-40i) Ohm. Then the impedance seen by TX1 & TX2 is given by its absolute value. 

|Z| = √(R² + X²) -> √(7² + (-40)²) -> |Z|=40.6 Ohms 

 

So, it is always about combination of the real and imaginary part and their absolute value. 

The absolute value should not drop bellow approx 15 Ohms which might lead to TX overcurrent. 

 

BR

Tomas 

 

 

 

 

 

 

 

 

0 Kudos
Reply
4,034 Views
KLP
Contributor I

So this is a result I can consider quite decent?

KLP_0-1744358747110.png

 

 

0 Kudos
Reply
3,903 Views
Tomas_Parizek
NXP Employee
NXP Employee
Hello KLP,

Yes, this is perfect !!

BR
Tomas
0 Kudos
Reply
%3CLINGO-SUB%20id%3D%22lingo-sub-1956334%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3EPN7160%20big%20SWR%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-1956334%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3E%3CP%3EHello.%3C%2FP%3E%3CP%3EI%20have%20a%20small%20issue%20with%20matching%20the%20antenna%20to%20the%20PN7160%20circuit.%20Everything%20seems%20fine%2C%20but%20not%20completely.%20The%20system%20operates%20in%20a%20single-ended%20configuration%20with%20the%20DXW21BN2511N%23%20balun%2C%20in%20the%20setup%20as%20shown%20below.%3C%2FP%3E%3CP%3E%3CSPAN%20class%3D%22lia-inline-image-display-wrapper%20lia-image-align-inline%22%20image-alt%3D%22Piecuch_0-1726643700857.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cspan%20class%3D%22lia-inline-image-display-wrapper%22%20image-alt%3D%22Piecuch_0-1726643700857.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cimg%20src%3D%22https%3A%2F%2Fcommunity.nxp.com%2Ft5%2Fimage%2Fserverpage%2Fimage-id%2F299617iBA502C052FE169A8%2Fimage-size%2Fmedium%3Fv%3Dv2%26amp%3Bpx%3D400%22%20role%3D%22button%22%20title%3D%22Piecuch_0-1726643700857.png%22%20alt%3D%22Piecuch_0-1726643700857.png%22%20%2F%3E%3C%2Fspan%3E%3C%2FSPAN%3E%3C%2FP%3E%3CP%3EX1%20and%20X2%20are%20inductors%20LQW18CNR16J00D%20(S1P%20models).%20X3%20is%20the%20S1P%20measured%20using%20a%20VNA%20together%20with%20the%20balun.%20The%20simulation%20shows%20correct%20component%20selection%3A%3C%2FP%3E%3CP%3E%3CSPAN%20class%3D%22lia-inline-image-display-wrapper%20lia-image-align-inline%22%20image-alt%3D%22Piecuch_1-1726643747343.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cspan%20class%3D%22lia-inline-image-display-wrapper%22%20image-alt%3D%22Piecuch_1-1726643747343.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cimg%20src%3D%22https%3A%2F%2Fcommunity.nxp.com%2Ft5%2Fimage%2Fserverpage%2Fimage-id%2F299618iAC3A2C3B26A6B3DF%2Fimage-size%2Fmedium%3Fv%3Dv2%26amp%3Bpx%3D400%22%20role%3D%22button%22%20title%3D%22Piecuch_1-1726643747343.png%22%20alt%3D%22Piecuch_1-1726643747343.png%22%20%2F%3E%3C%2Fspan%3E%3C%2FSPAN%3E%3C%2FP%3E%3CP%3EThe%20measurement%20in%20the%20actual%20circuit%20is%20very%20similar%3A%3C%2FP%3E%3CP%3E%3CSPAN%20class%3D%22lia-inline-image-display-wrapper%20lia-image-align-inline%22%20image-alt%3D%22Piecuch_2-1726643823881.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cspan%20class%3D%22lia-inline-image-display-wrapper%22%20image-alt%3D%22Piecuch_2-1726643823881.png%22%20style%3D%22width%3A%20388px%3B%22%3E%3Cimg%20src%3D%22https%3A%2F%2Fcommunity.nxp.com%2Ft5%2Fimage%2Fserverpage%2Fimage-id%2F299619iBBB5D4C28D89A54E%2Fimage-size%2Fmedium%3Fv%3Dv2%26amp%3Bpx%3D400%22%20role%3D%22button%22%20title%3D%22Piecuch_2-1726643823881.png%22%20alt%3D%22Piecuch_2-1726643823881.png%22%20%2F%3E%3C%2Fspan%3E%3C%2FSPAN%3E%3C%2FP%3E%3CBR%20%2F%3E%3CP%3EHowever%2C%20the%20SWR%20measurement%20indicates%20that%20the%20circuit%20is%20not%20well%20compensated.%3C%2FP%3E%3CP%3E%3CSPAN%20class%3D%22lia-inline-image-display-wrapper%20lia-image-align-inline%22%20image-alt%3D%22Piecuch_3-1726643874136.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cspan%20class%3D%22lia-inline-image-display-wrapper%22%20image-alt%3D%22Piecuch_3-1726643874136.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cimg%20src%3D%22https%3A%2F%2Fcommunity.nxp.com%2Ft5%2Fimage%2Fserverpage%2Fimage-id%2F299620i782986C26905E012%2Fimage-size%2Fmedium%3Fv%3Dv2%26amp%3Bpx%3D400%22%20role%3D%22button%22%20title%3D%22Piecuch_3-1726643874136.png%22%20alt%3D%22Piecuch_3-1726643874136.png%22%20%2F%3E%3C%2Fspan%3E%3C%2FSPAN%3E%3C%2FP%3E%3CBR%20%2F%3E%3CP%3EThe%20simulation%20shows%20the%20same%20as%20well%3A%3C%2FP%3E%3CP%3E%3CSPAN%20class%3D%22lia-inline-image-display-wrapper%20lia-image-align-inline%22%20image-alt%3D%22Piecuch_4-1726643913845.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cspan%20class%3D%22lia-inline-image-display-wrapper%22%20image-alt%3D%22Piecuch_4-1726643913845.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cimg%20src%3D%22https%3A%2F%2Fcommunity.nxp.com%2Ft5%2Fimage%2Fserverpage%2Fimage-id%2F299621iBB79D25F76B4A9FD%2Fimage-size%2Fmedium%3Fv%3Dv2%26amp%3Bpx%3D400%22%20role%3D%22button%22%20title%3D%22Piecuch_4-1726643913845.png%22%20alt%3D%22Piecuch_4-1726643913845.png%22%20%2F%3E%3C%2Fspan%3E%3C%2FSPAN%3E%3C%2FP%3E%3CP%3EThe%20system%20works%20and%20reads%20NFC%20cards%2C%20but%20sometimes%20it%20freezes%2C%20generating%20a%20continuous%2013.56%20MHz%20signal%2C%20which%20leads%20to%20overheating.%20Where%20could%20the%20problem%20lie%3F%3C%2FP%3E%3CBR%20%2F%3E%3CP%3EKrzysztof%3C%2FP%3E%3CBR%20%2F%3E%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-2079929%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3ERe%3A%20PN7160%20big%20SWR%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-2079929%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3EHello%20KLP%2C%20%3CBR%20%2F%3E%3CBR%20%2F%3EYes%2C%20this%20is%20perfect%20!!%20%3CBR%20%2F%3E%3CBR%20%2F%3EBR%3CBR%20%2F%3ETomas%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-2078890%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3ERe%3A%20PN7160%20big%20SWR%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-2078890%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3E%3CP%3ESo%20this%20is%20a%20result%20I%20can%20consider%20quite%20decent%3F%3C%2FP%3E%3CP%3E%3CSPAN%20class%3D%22lia-inline-image-display-wrapper%20lia-image-align-inline%22%20image-alt%3D%22KLP_0-1744358747110.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cspan%20class%3D%22lia-inline-image-display-wrapper%22%20image-alt%3D%22KLP_0-1744358747110.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cimg%20src%3D%22https%3A%2F%2Fcommunity.nxp.com%2Ft5%2Fimage%2Fserverpage%2Fimage-id%2F332642iAB45F0DE1A90DF0B%2Fimage-size%2Fmedium%3Fv%3Dv2%26amp%3Bpx%3D400%22%20role%3D%22button%22%20title%3D%22KLP_0-1744358747110.png%22%20alt%3D%22KLP_0-1744358747110.png%22%20%2F%3E%3C%2Fspan%3E%3C%2FSPAN%3E%3C%2FP%3E%3CBR%20%2F%3E%3CBR%20%2F%3E%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-2076750%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3ERe%3A%20PN7160%20big%20SWR%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-2076750%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3E%3CP%3EHello%26nbsp%3B%3CA%20href%3D%22https%3A%2F%2Fcommunity.nxp.com%2Ft5%2Fuser%2Fviewprofilepage%2Fuser-id%2F240723%22%20target%3D%22_blank%22%3E%40KLP%3C%2FA%3E%26nbsp%3B%2C%26nbsp%3B%3C%2FP%3E%0A%3CP%3EIdeally%2C%20if%20the%20antenna%20is%20properly%20tuned.%20We%20recomenend%20to%20have%20imaginary%20offset%20%2B-3%20Ohms%20from%20real%20axis%20for%20best%20efficiency.%20E.g.%20If%20your%20target%20tuning%20should%20be%2020%20Ohm.%20Then%20It%20is%20acceptable%20to%20have%20it%20as%20%3CSTRONG%3E20%2B-3i%20Ohm%3C%2FSTRONG%3E.%26nbsp%3B%3C%2FP%3E%0A%3CP%3EIf%20you%20detune%20the%20antenna%20by%20a%20card%20or%20a%20different%20object%2C%20the%20impedance%20will%20change%20to%20e.g.%20(7-40i)%20Ohm.%20Then%20the%20impedance%20seen%20by%20TX1%20%26amp%3B%20TX2%20is%20given%20by%20its%20absolute%20value.%26nbsp%3B%3C%2FP%3E%0A%3CP%3E%3CSPAN%3E%7CZ%7C%20%3D%26nbsp%3B%3C%2FSPAN%3E%E2%88%9A(R%C2%B2%20%2B%20X%C2%B2)%20-%26gt%3B%26nbsp%3B%E2%88%9A(7%C2%B2%20%2B%20(-40)%C2%B2)%20-%26gt%3B%26nbsp%3B%3CSPAN%3E%7CZ%7C%3D%3CSTRONG%3E40.6%20Ohms%26nbsp%3B%3C%2FSTRONG%3E%3C%2FSPAN%3E%3C%2FP%3E%0A%3CBR%20%2F%3E%0A%3CP%3ESo%2C%20it%20is%20always%20about%20combination%20of%20the%20real%20and%20imaginary%20part%20and%20their%20absolute%20value.%26nbsp%3B%3C%2FP%3E%0A%3CP%3EThe%20absolute%20value%20should%20not%20drop%20bellow%20approx%2015%20Ohms%20which%20might%20lead%20to%20TX%20overcurrent.%26nbsp%3B%3C%2FP%3E%0A%3CBR%20%2F%3E%0A%3CP%3EBR%3C%2FP%3E%0A%3CP%3ETomas%26nbsp%3B%3C%2FP%3E%0A%3CBR%20%2F%3E%0A%3CBR%20%2F%3E%0A%3CBR%20%2F%3E%0A%3CBR%20%2F%3E%0A%3CBR%20%2F%3E%0A%3CBR%20%2F%3E%0A%3CBR%20%2F%3E%0A%3CBR%20%2F%3E%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-2075792%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3ERe%3A%20PN7160%20big%20SWR%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-2075792%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3E%22What%20values%20of%20imaginary%20resistance%20are%20safe%20for%20the%20circuit%3F%22**%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-1966977%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3ERe%3A%20PN7160%20big%20SWR%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-1966977%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3E%3CP%3Ehi%20Tomas%2C%3C%2FP%3E%0A%3CBR%20%2F%3E%0A%3CP%3EFollowing%20your%20recomendations%20changes%20are%20made.%20However%20the%20issue%20still%20remains.%20Let%20me%20followup%20with%20more%20details.%20Please%20find%20below%20current%20customer's%20schematic.%20Kindly%20suggest%20what%20else%20can%20be%20modified.%3C%2FP%3E%0A%3CP%3E%3CSPAN%20class%3D%22lia-inline-image-display-wrapper%20lia-image-align-inline%22%20image-alt%3D%22vyacheslavguzhv_0-1728052297205.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cspan%20class%3D%22lia-inline-image-display-wrapper%22%20image-alt%3D%22vyacheslavguzhv_0-1728052297205.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cimg%20src%3D%22https%3A%2F%2Fcommunity.nxp.com%2Ft5%2Fimage%2Fserverpage%2Fimage-id%2F302734iB5233C4A889AF1B0%2Fimage-size%2Fmedium%3Fv%3Dv2%26amp%3Bpx%3D400%22%20role%3D%22button%22%20title%3D%22vyacheslavguzhv_0-1728052297205.png%22%20alt%3D%22vyacheslavguzhv_0-1728052297205.png%22%20%2F%3E%3C%2Fspan%3E%3C%2FSPAN%3E%3C%2FP%3E%0A%3CBR%20%2F%3E%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-1965559%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3ERe%3A%20PN7160%20big%20SWR%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-1965559%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3EYES.%20The%20measured%20current%20is%20244%5BmA%5D%20and%20the%20calculated%20current%20is%20approximately%20180%5BmA%5D.%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-1964210%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3ERe%3A%20PN7160%20big%20SWR%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-1964210%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3E%3CP%3EHello%20KLP%2C%26nbsp%3B%3C%2FP%3E%0A%3CP%3EAre%20you%20refering%20to%20this%20Antenna%20calculation%20excel%20sheet%3F%26nbsp%3B%3C%2FP%3E%0A%3CP%3E%3CSPAN%20class%3D%22lia-inline-image-display-wrapper%20lia-image-align-inline%22%20image-alt%3D%22Tomas_Parizek_0-1727678092881.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cspan%20class%3D%22lia-inline-image-display-wrapper%22%20image-alt%3D%22Tomas_Parizek_0-1727678092881.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cimg%20src%3D%22https%3A%2F%2Fcommunity.nxp.com%2Ft5%2Fimage%2Fserverpage%2Fimage-id%2F301897iD1CF0E4FCE9D8EE8%2Fimage-size%2Fmedium%3Fv%3Dv2%26amp%3Bpx%3D400%22%20role%3D%22button%22%20title%3D%22Tomas_Parizek_0-1727678092881.png%22%20alt%3D%22Tomas_Parizek_0-1727678092881.png%22%20%2F%3E%3C%2Fspan%3E%3C%2FSPAN%3E%3C%2FP%3E%0A%3CP%3EOr%20the%20TX%20driver%20current%20calculation%20I%20shared%20before%20%3F%3C%2FP%3E%0A%3CBR%20%2F%3E%0A%3CP%3EBR%3C%2FP%3E%0A%3CP%3ETomas%26nbsp%3B%3C%2FP%3E%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-1962687%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3ERe%3A%20PN7160%20big%20SWR%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-1962687%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3EAre%20the%20calculations%20from%20the%20spreadsheet%20the%20same%20when%20using%20the%20antenna%20with%20a%20balun%20as%20in%20the%20version%20without%20the%20balun%3F%20I%20have%20significant%20discrepancies%20between%20the%20spreadsheet%2C%20the%20simulation%2C%20and%20the%20actual%20circuit.%3CBR%20%2F%3E%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-1962406%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3ERe%3A%20PN7160%20big%20SWR%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-1962406%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3E%3CP%3EHello%2C%26nbsp%3B%3C%2FP%3E%0A%3CBR%20%2F%3E%0A%3CP%3EThanks%20for%20your%20feedback%20!%20As%20the%20limit%20is%20250mA%2C%20you%20are%20already%20quite%20close.%20I%20would%20suggest%20to%20sligly%20increase%20the%20tuning%20impedance%20(from%2020%20Ohms%20to%20e.g.%2023-25%20Ohms)%20or%20decrease%20the%20TXLDO%20output%20voltage.%26nbsp%3B%3C%2FP%3E%0A%3CP%3EThis%20should%20decrease%20the%20continuous%20current%20to%20approx%20230%20mA.%26nbsp%3B%3C%2FP%3E%0A%3CBR%20%2F%3E%0A%3CP%3EBR%3C%2FP%3E%0A%3CBR%20%2F%3E%0A%3CP%3ETomas%26nbsp%3B%3C%2FP%3E%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-1958798%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3ERe%3A%20PN7160%20big%20SWR%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-1958798%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3EContinuous%20current%20is%20244%20mA.%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-1957416%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3ERe%3A%20PN7160%20big%20SWR%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-1957416%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3E%3CP%3EYes%2C%20I%20confirm.%20After%20changing%20the%20generator's%20impedance%20from%2050%CE%A9%20to%2020%CE%A9%2C%20the%20SWR%20now%20shows%20correctly.%3C%2FP%3E%3CP%3E%3CSPAN%20class%3D%22lia-inline-image-display-wrapper%20lia-image-align-inline%22%20image-alt%3D%22KLP_0-1726733395012.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cspan%20class%3D%22lia-inline-image-display-wrapper%22%20image-alt%3D%22KLP_0-1726733395012.png%22%20style%3D%22width%3A%20333px%3B%22%3E%3Cimg%20src%3D%22https%3A%2F%2Fcommunity.nxp.com%2Ft5%2Fimage%2Fserverpage%2Fimage-id%2F299940iD38FD960AE5B125F%2Fimage-size%2Fmedium%3Fv%3Dv2%26amp%3Bpx%3D400%22%20role%3D%22button%22%20title%3D%22KLP_0-1726733395012.png%22%20alt%3D%22KLP_0-1726733395012.png%22%20%2F%3E%3C%2Fspan%3E%3C%2FSPAN%3E%3C%2FP%3E%3CBR%20%2F%3E%3CP%3E%3CSPAN%20class%3D%22lia-inline-image-display-wrapper%20lia-image-align-inline%22%20image-alt%3D%22KLP_1-1726733424742.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cspan%20class%3D%22lia-inline-image-display-wrapper%22%20image-alt%3D%22KLP_1-1726733424742.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cimg%20src%3D%22https%3A%2F%2Fcommunity.nxp.com%2Ft5%2Fimage%2Fserverpage%2Fimage-id%2F299941i1FF80B1C15198E0E%2Fimage-size%2Fmedium%3Fv%3Dv2%26amp%3Bpx%3D400%22%20role%3D%22button%22%20title%3D%22KLP_1-1726733424742.png%22%20alt%3D%22KLP_1-1726733424742.png%22%20%2F%3E%3C%2Fspan%3E%3C%2FSPAN%3E%3C%2FP%3E%3CP%3E%3CSPAN%20class%3D%22lia-inline-image-display-wrapper%20lia-image-align-inline%22%20image-alt%3D%22KLP_2-1726733464958.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cspan%20class%3D%22lia-inline-image-display-wrapper%22%20image-alt%3D%22KLP_2-1726733464958.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cimg%20src%3D%22https%3A%2F%2Fcommunity.nxp.com%2Ft5%2Fimage%2Fserverpage%2Fimage-id%2F299942iC71B029AEB27A2D2%2Fimage-size%2Fmedium%3Fv%3Dv2%26amp%3Bpx%3D400%22%20role%3D%22button%22%20title%3D%22KLP_2-1726733464958.png%22%20alt%3D%22KLP_2-1726733464958.png%22%20%2F%3E%3C%2Fspan%3E%3C%2FSPAN%3E%3C%2FP%3E%3CP%3EI%20will%20try%20to%20measure%20the%20current%2C%20but%20it%20may%20take%20a%20while%20as%20this%20sometimes%20happens%20only%20after%20several%20hours%20of%20operation.%3C%2FP%3E%3CBR%20%2F%3E%3CP%3EKrzysztof%3C%2FP%3E%3C%2FLINGO-BODY%3E%3CLINGO-SUB%20id%3D%22lingo-sub-1957327%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3ERe%3A%20PN7160%20big%20SWR%3C%2FLINGO-SUB%3E%3CLINGO-BODY%20id%3D%22lingo-body-1957327%22%20slang%3D%22en-US%22%20mode%3D%22CREATE%22%3E%3CP%3ECze%C5%9B%C4%87%20Krzysztof%2C%26nbsp%3B%3C%2FP%3E%0A%3CP%3EI%20would%20say%20that%20the%20matching%20looks%20fine.%20You%20have%20almost%20exactly%2020%20Ohm.%26nbsp%3B%3C%2FP%3E%0A%3CP%3EThe%20reason%20why%20you%20see%20this%20VSWR%20is%20that%20you%20are%20using%2050%20Ohm%20impedance%20system%20for%20your%20measurement%20while%20the%20impedance%20of%20the%20circuit%20is%20matched%20to%2020%20Ohm.%26nbsp%3B%3C%2FP%3E%0A%3CP%3EWe%20don%C2%B4t%20use%20the%20VSWR%20because%20the%20output%20impedance%20of%20the%20chip%20is%20not%2050%20Ohm.%26nbsp%3B%3C%2FP%3E%0A%3CP%3EWe%20rather%20use%20this%20approach%20%3A%3C%2FP%3E%0A%3CP%3E%3CSPAN%20class%3D%22lia-inline-image-display-wrapper%20lia-image-align-inline%22%20image-alt%3D%22Tomas_Parizek_0-1726729772921.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cspan%20class%3D%22lia-inline-image-display-wrapper%22%20image-alt%3D%22Tomas_Parizek_0-1726729772921.png%22%20style%3D%22width%3A%20400px%3B%22%3E%3Cimg%20src%3D%22https%3A%2F%2Fcommunity.nxp.com%2Ft5%2Fimage%2Fserverpage%2Fimage-id%2F299910i5FFB82E533BF1335%2Fimage-size%2Fmedium%3Fv%3Dv2%26amp%3Bpx%3D400%22%20role%3D%22button%22%20title%3D%22Tomas_Parizek_0-1726729772921.png%22%20alt%3D%22Tomas_Parizek_0-1726729772921.png%22%20%2F%3E%3C%2Fspan%3E%3C%2FSPAN%3E%3C%2FP%3E%0A%3CP%3EAnd%20then%20the%20output%20power%20of%20the%20chip%20respectively%20its%20input%20current%20can%20be%20calculated%20as%20described%20here%20-%26gt%3B%26nbsp%3B%3C%2FP%3E%0A%3CP%3E%3CA%20href%3D%22https%3A%2F%2Fcommunity.nxp.com%2Ft5%2FNFC%2FPN7160-PN7161-DPC-Symmetric-Tuning-Values%2Fm-p%2F1922063%2Fthread-id%2F11983%23M11984%22%20target%3D%22_blank%22%3Ehttps%3A%2F%2Fcommunity.nxp.com%2Ft5%2FNFC%2FPN7160-PN7161-DPC-Symmetric-Tuning-Values%2Fm-p%2F1922063%2Fthread-id%2F11983%23M11984%3C%2FA%3E%3C%2FP%3E%0A%3CBR%20%2F%3E%0A%3CP%3EAbout%20the%20overheating.%20Can%20you%20check%20the%20TXLDO%20input%20current%20(VDD(UP)%20pin)%20during%20the%20continuios%2013.56%20MHz%20%3F%20This%20current%20shall%20not%20exceed%20250%20mA.%26nbsp%3B%3C%2FP%3E%0A%3CBR%20%2F%3E%0A%3CP%3EBR%3C%2FP%3E%0A%3CP%3ETomas%26nbsp%3B%3C%2FP%3E%0A%3CP%3ECustomer%20Application%20Support%20Enginner%26nbsp%3B%3C%2FP%3E%3C%2FLINGO-BODY%3E