Hi all;
I need to know the minimum value of Vrefn. I suppose that according with the manual ((Vrefp-Vrefn)/2) + Vrefn = Vdd/2. Therefore Vrefnmaximum = Vdd - Vrefminimum.
If Vdd=3.3v and Vrefminimum is 2.4v (acording with the manual).
Is Vrefnmaximum 0.9v and then is the maximum sensibility 0.366 mV?
Thanks so much and regards. Daniel.
Yes, I am using a LPC824.
Regards. Daniel.
Hi,
Yes, Vrefn max= 0.9v however
1 LSB = (Vrefp - Vss)/4096 according with the datasheet
Have a great day,
Sol
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Hi Soledad;
LPC82x.pdf Fig 39 image does not indicates a conection between Vrefn and Vss?
I don't understand... Vrefn does not fix the minimum value of the full scale (FS)?
I thought that result of a conversion is:
*A parenthesis between (Vinn-Vrefn) is mising)
But in UM10800.pdf at page 322 "Perform a single ADC conversion using a software trigger" it says that The result of the conversion is (4095 x VIN)/(VREFP - VREFN).
On one hand this would mean that there isn't an Vrefn offset and on the other hand this would mean that LSB (minimum)[v] ocurrs when Vrefp(minimum) and Vrefn(maximum):
I need more information about the problem please.
Regards. Daniel.
Hello Daniel,
Could you please mention the device you are using?
Regards
Sol