the internal pull resistor is automatically disabled

cancel
Showing results for 
Show  only  | Search instead for 
Did you mean: 

the internal pull resistor is automatically disabled

Jump to solution
642 Views
jun1
Contributor V

Hi.

I am looking at the KM series' reference manual.
The following explanation is given in "11.6.1 Pin control".
"Note that the internal pull resistor is automatically disabled whenever the output buffer is enabled for the Pull Enable bit to remain set."

(1) Does the GPIO output port indicate that the built-in pull resistance can not be set or used?
(2) Is it pull enable, but is the output port pull resistance not allowed?
(3) In which case should you use the above? (The register is a pull permission, but there is no pull resistance.)

I hope you will.

0 Kudos
Reply
1 Solution
576 Views
jingpan
NXP TechSupport
NXP TechSupport

Hi jun,

1. Yes, when the pin work as GPIO output, pull resistor is disabled.

2.Yes, it's sure that the pull resistor has no influence on output. And the Pull Enable bit in PCR register will not change.

3. When pin in output status. The functions apply across all digital pin muxing modes and individual peripherals do not
override the configuration in the Pin Control register.

Regards,

Jing

View solution in original post

0 Kudos
Reply
1 Reply
577 Views
jingpan
NXP TechSupport
NXP TechSupport

Hi jun,

1. Yes, when the pin work as GPIO output, pull resistor is disabled.

2.Yes, it's sure that the pull resistor has no influence on output. And the Pull Enable bit in PCR register will not change.

3. When pin in output status. The functions apply across all digital pin muxing modes and individual peripherals do not
override the configuration in the Pin Control register.

Regards,

Jing

0 Kudos
Reply