Hi community,
Our partner have some questiosn about i.MX6SDL EIM.
They understand the EIM access will be burst when BL=Continuous burst length and APR=0 (synchronous access).
Then, please see their questions as following.
[Q1]
The finish timing of burst access is handled by i.MX6 EIM if WFL=1 and RFL=1.
Is this correct?
[Q2]
With the condition of Q1, software can execute a fix length access (e.g. single access).
Is this correct?
[Q3]
The finish timing of burst access is handled by EIM slave if WFL=1 and RFL=1.
Is this correct?
[Q4]
With the condition of Q2, EIM slave finishes a access by WAIT signal.
Is this correct?
Best Regards,
Satoshi Shimoda
解決済! 解決策の投稿を見る。
Hi Satoshi
RFL,WFL do not have relation to burst behaviour.
RFL,WFL=0 means that supported WAIT signal, it is
checked after RWSC/ WWSC cycles.
RFL,WFL=1 means that WAIT signal is ignored , burst (if any,
may be just one access, that is single beat in burst)
starts after RWSC/ WWSC cycles.
IMX6SDLRM Figure 22-12 shows such waveforms
IMX6DQRM p.1047 Figure 22-12 gives example of "burst length =4" -correspond
to RD0,1,2,3 and "number of skipped BCLK =3" : 2 - WAIT and one due to RWSC=1.
Best regards
igor
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Hi Satoshi
RFL,WFL do not have relation to burst behaviour.
RFL,WFL=0 means that supported WAIT signal, it is
checked after RWSC/ WWSC cycles.
RFL,WFL=1 means that WAIT signal is ignored , burst (if any,
may be just one access, that is single beat in burst)
starts after RWSC/ WWSC cycles.
IMX6SDLRM Figure 22-12 shows such waveforms
IMX6DQRM p.1047 Figure 22-12 gives example of "burst length =4" -correspond
to RD0,1,2,3 and "number of skipped BCLK =3" : 2 - WAIT and one due to RWSC=1.
Best regards
igor
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Note: If this post answers your question, please click the Correct Answer button. Thank you!
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