Adding a task without the while(1) loop

[michaelsteffenf]

Generic question for an RTOS application:

Using FreeRToS (or MQX), what happens when the While(1) loop is let out of the task?

Here is the task create code:

/* Run GPIO State Algorithm */

xTaskCreate(chkGPIOState, "GPIOStateAlgorithm",

configMINIMAL_STACK_SIZE, NULL, (tskIDLE_PRIORITY + 1UL),

(TaskHandle_t *) NULL);

Here is the task:

static void chkGPIOState(void)

{

//while (1) {                                                                            // WHAT HAPPENS TO THE RTOS IF THE while (1) is omitted?

Board_UARTPutSTR("\x1B[2J"); // clear screen

Board_UARTPutSTR("\x1B[1;1H"); // set position to 1,1

pinvalue8=Chip_GPIO_GetPinState(LPC_GPIO_PORT, 0, 13);

pinvalue7=Chip_GPIO_GetPinState(LPC_GPIO_PORT, 0, 14);

pinvalue6=Chip_GPIO_GetPinState(LPC_GPIO_PORT, 0, 15);

pinvalue5=Chip_GPIO_GetPinState(LPC_GPIO_PORT, 0, 12);

Print_Val("GPIO_P0_13 = ", pinvalue8);

Print_Val("GPIO_P0_14 = ", pinvalue7);

Print_Val("GPIO_P0_15 = ", pinvalue6);

Print_Val("GPIO_P0_12 = ", pinvalue5);

vTaskDelay(configTICK_RATE_HZ/2);

//}

}

Michael Steffen

Senior Field Applications Engineer

Member of the Technical Staff

NXP Semiconductors

[danielchen]

Hi Michael:

With while (1) loop, GPIO state will print on the screen, and will refresh every ( configTICK_RATE_HZ/2) time.

Without while (1) loop , GPIO state will print only once, not refresh.

Regards

Daniel