Hello, I'm trying use ADC at FRDM-K22F, it's working, but I didn't get success on calculate the ADC clock. I'm using http://www.nxp.com/products/microcontrollers-and-processors/arm-processors/kinetis-cortex-m-mcus/adc... for calculate the ADC clock, but the result the calculator don't is equal at result of conversion.
I'm setting my ADC clock this way:
adcUserConfig.resolution = kAdc16ResolutionBitOf16;
adcUserConfig.highSpeedEnable = false;
adcUserConfig.clkSrc = kAdc16ClkSrcOfBusClk;
adcUserConfig.lowPowerEnable = false;
adcUserConfig.asyncClkEnable = false;
adcUserConfig.longSampleTimeEnable = false;
adcUserConfig.longSampleCycleMode = kAdc16LongSampleCycleOf24;
adcUserConfig.clkDividerMode = kAdc16ClkDividerOf8;
ADC16_DRV_Init(ADC16_INSTANCE, &adcUserConfig);
What's the result of ADC clock for this example?
Thanks.
Hi, Adriano,
Regarding your question about the ADC clock frequency, from hardware perspective, I suggest you should check the following register setting.
1)pls check the ADCx_CFG1[ADICLK], which selects the clock source of ADC.
For K22, I copied the part here:
2)there is divider set up in the ADCx_CFG[ADIV], I copy it here.
Clock Divide Select
Selects the divide ratio used by the ADC to generate the internal clock ADCK.
00 The divide ratio is 1 and the clock rate is input clock.
01 The divide ratio is 2 and the clock rate is (input clock)/2.
10 The divide ratio is 4 and the clock rate is (input clock)/4.
11 The divide ratio is 8 and the clock rate is (input clock)/8.
For your code, I think you select bus clock as ADC clock source with ADICLK bit=00 in binary, the divider is 8 with ADIV bits=11 in binary, the ADC clock frequency is (bus clock)/8. I do not know your bus clock frequency, it is dependent on the MCG mode, and SIM_CLKDIV1 register setting.
Hope it can help you.
B R
Xiangjun Rong
Hi Xiangjun,
My bus clock is 60 MHz divided for 8, so, my ADC Clock is 7,5 MHz. Now, I want find the conversion time per sample, I have to use this formula (ConversionTime = SFCAdder + AVGNUM x (BCT + LSTAdder + HSCAdder)) ?
Thank you very much.