Adding Interrupt Vector problem.

[Heppell]

Hey guys,

I'm using 9S12X and I am trying to use the SPI interrupt at address 0xFFD8, I've tried using the instruction:
VECTOR ADDRESS 0xFFD8 eeSPI_ISR
or
VECTOR 19 eeSPI_ISR
in the .PRM file but keep getting the error: "Initialization of Vector eeSPI_ISR failed because of over- underflow of vector value.". I'm not sure how to remedy this situation, any help would be appreciated, thanks.

[CompilerGuru]

Interrupt vector functions must be allocated non banked, say in the 16 bit addressable area.
Error message basically means that the linker would have to cut a 24 bit interrupt function handler address
into a 16 bit vector entry.

So in order to allocate the handler non banked, add a

#pragma push
#pragma CODE_SEG __NEAR_SEG NON_BANKED

before the interrupt handler and a

#pragma pop

afterwards.

Daniel

[Heppell]

I misunderstood your solution, I also have been trying to build a vector table instead of this shorter solution. Anyway, I did have some sizing issues which rung a bell, now implementing this code the size issue goes away. I will test this after lunch, hopefully it works out, Thanks

#pragma CODE_SEG __NEAR_SEG NON_BANKED        /* these functions have to be allocated in the non banked area */
extern void _Startup();
extern void eeSPI_ISR();
static interrupt void dummit(void) {}   
#pragma CODE_SEG DEFAULT

[Heppell]

Hey Daniel,
Thanks for replying, taking your advice, generates the same error code:

void interrupt eeSPI_ISR(void)
{
   #pragma push
   #pragma CODE_SEG__NEAR_SEG NON_BANKED
   eeStateMachine ();
   #pragma pop
}

Link Error   : L1108: Initializing of Vector eeSPI_ISR failed because of over- or underflow of vector value