Task with priority 8 and kernel isr how works the system?

[admin]

Hi,

I have a system that works with MQX RTOS 3.5 on Coldifire MCF52259 one task always active with priority 8 plus a kernel isr

TASK_TEMPLATE_STRUCT MQX_template_list[] =
{
//  Task number, Entry point, Stack, Pri, String, Auto?
    { MAIN_TASK, Main_task,   5000,  8,   "main_prof", MQX_AUTO_START_TASK, 0L, 0},
    { 0,         0,           0,     0,   0,      0, 0L, 0                       }
};

#define GPT0_INTERRUPT_LEVEL              7
#define GPT0_INTERRUPT_PRIORITY        7

_int_install_kernel_isr(MCF5225_INT_TIMA_C0F,(void (_CODE_PTR_)(void))isrINT_CF0);

_mcf5225_int_init(MCF5225_INT_TIMA_C0F,GPT0_INTERRUPT_LEVEL,GPT0_INTERRUPT_PRIORITY,TRUE);

With this configuration, when my hw interrupt starts, the system blocks the task and execute the interrupt or I need to use task queue inside interrupt kernel for suspending the task?

[Geek19]

Hi Shinji,

    I am having difficulty getting my kernel interrupt working for me, I do not know how/what to save/restore before and after my function call in kernel ISR, I was wondering if you could explain to me about your approach on how you are doing your kernel ISR?

Thanks;

Geek19

[admin]

Reading the MQX User guide I see  there are restrictions on ISRs, so if I use a kernel interrupt I can't use _taskq_suspend()
_taskq_suspend_task()

these restrictions are valid also for kernel interrupts?

[PetrL]

The kernel isr is not handled by MQX at all - it must not call any MQX function.

You should pass information to other tasks (if required) by an application-implemented mechanism (usually
ring buffers with head and tail pointers and total size fields).

For more information see Reference Manual chapter:

2.1.45 _int_install_kernel_isr

PetrL