CAN Current Source Capability

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CAN Current Source Capability

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bjrajendra
Senior Contributor I

Hello all,

Currently I'm using S32K14x device. I would like to know the current sink capability of CAN RX Module.

I have seen I/O current sinking capability mentioned as 5mA when used as IO pin as shown below. Will it work same with CAN module of any baud rate.

pastedImage_1.png

Kindly help with suitable documents.

Raju

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danielmartynek
NXP TechSupport
NXP TechSupport

Hi Raju,

The RXD pin of the transceiver is an output, it is not an input.

As you can see below, there is a push-pull driver.

pastedImage_1.png

Specified as follows:

pastedImage_1.png

The RXD pin of the transceiver is connected to the CAN_RX pin of the MCU.

Where the CAN_RX pin is an input driven by the RXD driver.

pastedImage_3.png

Regards,

Daniel

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danielmartynek
NXP TechSupport
NXP TechSupport

Hello Raju,

The 5mA sink current applies for output pins only.

The CAN_RX function is an input, it is floating.

Regards,

Daniel 

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bjrajendra
Senior Contributor I

Hi Daniel,

Thanks for the response.

In fact, we're planning to connect two TJA1050 transceiver IC to one CAN_TX & CAN_RX port. This transceiver IC has an RX terminal in the range of 10mA. Thus is it possible for CAN_RX port to deliver the same.

I may be misunderstood. Kindly guide in meeting the requirement.

Raju.

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danielmartynek
NXP TechSupport
NXP TechSupport

Hi Raju,

The RXD pin of the transceiver is an output, it is not an input.

As you can see below, there is a push-pull driver.

pastedImage_1.png

Specified as follows:

pastedImage_1.png

The RXD pin of the transceiver is connected to the CAN_RX pin of the MCU.

Where the CAN_RX pin is an input driven by the RXD driver.

pastedImage_3.png

Regards,

Daniel

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bjrajendra
Senior Contributor I

Thanks Daniel for the support.

Raju.

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