CAN Current Source Capability

cancel
Showing results for 
Show  only  | Search instead for 
Did you mean: 

CAN Current Source Capability

Jump to solution
1,203 Views
bjrajendra
Senior Contributor I

Hello all,

Currently I'm using S32K14x device. I would like to know the current sink capability of CAN RX Module.

I have seen I/O current sinking capability mentioned as 5mA when used as IO pin as shown below. Will it work same with CAN module of any baud rate.

pastedImage_1.png

Kindly help with suitable documents.

Raju

Labels (1)
0 Kudos
1 Solution
1,083 Views
danielmartynek
NXP TechSupport
NXP TechSupport

Hi Raju,

The RXD pin of the transceiver is an output, it is not an input.

As you can see below, there is a push-pull driver.

pastedImage_1.png

Specified as follows:

pastedImage_1.png

The RXD pin of the transceiver is connected to the CAN_RX pin of the MCU.

Where the CAN_RX pin is an input driven by the RXD driver.

pastedImage_3.png

Regards,

Daniel

View solution in original post

0 Kudos
4 Replies
1,083 Views
danielmartynek
NXP TechSupport
NXP TechSupport

Hello Raju,

The 5mA sink current applies for output pins only.

The CAN_RX function is an input, it is floating.

Regards,

Daniel 

0 Kudos
1,083 Views
bjrajendra
Senior Contributor I

Hi Daniel,

Thanks for the response.

In fact, we're planning to connect two TJA1050 transceiver IC to one CAN_TX & CAN_RX port. This transceiver IC has an RX terminal in the range of 10mA. Thus is it possible for CAN_RX port to deliver the same.

I may be misunderstood. Kindly guide in meeting the requirement.

Raju.

0 Kudos
1,084 Views
danielmartynek
NXP TechSupport
NXP TechSupport

Hi Raju,

The RXD pin of the transceiver is an output, it is not an input.

As you can see below, there is a push-pull driver.

pastedImage_1.png

Specified as follows:

pastedImage_1.png

The RXD pin of the transceiver is connected to the CAN_RX pin of the MCU.

Where the CAN_RX pin is an input driven by the RXD driver.

pastedImage_3.png

Regards,

Daniel

0 Kudos
1,083 Views
bjrajendra
Senior Contributor I

Thanks Daniel for the support.

Raju.

0 Kudos