Hi all,
I'm design a board using the iMX28 and I need to read 4 analog values in the range from 0 to 3.3 voltage and I would use the LRADC2..5 channels for this scope.
In the RM is write:
"For input channels (other than BATT, 5V, or VDDIO) with signals larger than 1.85 V,
the divide-by-two option should be set (HW_LRADC_CTRL2_DIVIDE_BY_TWO).
With the DIVIDE_BY_TWO option set, the maximum input voltage is VDDIO – 50mv."
but in the data sheet I the chapter 3.5.1.1 LRADC Electrical Specifications I read:
"DC input voltage 0-1.85 V"
Is it possible to apply an analog signal in the range from 0 to 3.3 voltage to the LRADC2...5 pins?
Regards
Stefano
Solved! Go to Solution.
Hi Stefano
RM is correct:
"For input channels (other than BATT, 5V, or VDDIO) with signals larger than 1.85 V,
the divide-by-two option should be set (HW_LRADC_CTRL2_DIVIDE_BY_TWO).
With the DIVIDE_BY_TWO option set, the maximum input voltage is VDDIO – 50mv."
So it is possible to apply an analog signal in the range from 0 to 3.3 voltage to the LRADC2...5 pins
Best regards
igor
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Hi Igor,
thank you for your quick answer.
Best regards
Stefano
Hi Stefano
RM is correct:
"For input channels (other than BATT, 5V, or VDDIO) with signals larger than 1.85 V,
the divide-by-two option should be set (HW_LRADC_CTRL2_DIVIDE_BY_TWO).
With the DIVIDE_BY_TWO option set, the maximum input voltage is VDDIO – 50mv."
So it is possible to apply an analog signal in the range from 0 to 3.3 voltage to the LRADC2...5 pins
Best regards
igor
-----------------------------------------------------------------------------------------------------------------------
Note: If this post answers your question, please click the Correct Answer button. Thank you!
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