What is GFLOPS number of i.MX6 Solo/ Dual / Quad processors ?

キャンセル
次の結果を表示 
表示  限定  | 次の代わりに検索 
もしかして: 

What is GFLOPS number of i.MX6 Solo/ Dual / Quad processors ?

ソリューションへジャンプ
3,010件の閲覧回数
doner_t
Contributor II

Hello,

I need to know GFLOP(Giga Floating Point operations per second ) number of i.MX6 Solo/Dual/ Quad processor. Could you help me ?

Regards,

Tugay

ラベル(3)
タグ(1)
1 解決策
1,780件の閲覧回数
dehuanxin
Contributor III

Depends on what kind of operations you are asking.

The Cortex A9 NEON core can do:

1) 4 single precision multiply/multiply-accumulate in 2 cycles

2) 4 other single precision operation in 1 cycle.

In practice it's not difficult to achieve 25%-30% code efficiency.

For a 1Ghz single core configuration, you can have 1GHz*25%*4 = 1GFLOPS for trivial operations, and 500M multiply-accumulate per second.

To get closer to the peak performance requires a lot of hand optimized NEON code. 25% of the peak is what I usually get from GCC NEON intrinsics.

元の投稿で解決策を見る

4 返答(返信)
1,781件の閲覧回数
dehuanxin
Contributor III

Depends on what kind of operations you are asking.

The Cortex A9 NEON core can do:

1) 4 single precision multiply/multiply-accumulate in 2 cycles

2) 4 other single precision operation in 1 cycle.

In practice it's not difficult to achieve 25%-30% code efficiency.

For a 1Ghz single core configuration, you can have 1GHz*25%*4 = 1GFLOPS for trivial operations, and 500M multiply-accumulate per second.

To get closer to the peak performance requires a lot of hand optimized NEON code. 25% of the peak is what I usually get from GCC NEON intrinsics.

1,780件の閲覧回数
doner_t
Contributor II

Hello,

Thank you very much !

But, now I need to know average power consumption of i.MX6 Solo/Dual/ Quad processor. I read datasheets. But not found a clear info.,

Regards,

Tugay

0 件の賞賛
返信
1,780件の閲覧回数
dehuanxin
Contributor III

i.MX6Q|i.MX 6Quad Processors|Quad Core|NXP

In the application note section you can find the power consumption measurements.

1,780件の閲覧回数
gusarambula
NXP TechSupport
NXP TechSupport

Thanks a lot, Dehuan Xin, for the information!

0 件の賞賛
返信