Battery life computation during BLE advertising

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Battery life computation during BLE advertising

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danf
Contributor II

Using the 88W8977 BLE+Wifi chip I'm trying to understand how long the device can stay powered while advertising (as a BLE peripheral) using battery power.

In the datasheet there is a current consumption table which has:

Bluetooth LE advertise(interval=1.28s): 0.047mA @ 1.8V.

(With Wifi in deep sleep mode).

Is the value (0.047mA) the average current draw? so the battery life is simply:

Battery Life = Battery Capacity (mAH) / 0.047mA. (Assuming a 1.8V battery?).

example: Battery Life = 2500 mAH / 0.047mA --> 53,191 hours or 6.07 years

I understand this life is only accurate if the device does nothing else which isn't realistic, but I want to know if I understand the chart correctly.

Thanks!

 

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mario_castaneda
NXP TechSupport
NXP TechSupport

Hi @danf,

You are right it is the average in this scenario, but you have to be aware of the Current consumption during
device initialization, the modules that you will have enabled WIFI, etc. 

Regards,

Mario

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danf
Contributor II

Thanks! That makes sense. I appreciate your help!

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mario_castaneda
NXP TechSupport
NXP TechSupport

Hi @danf,

You are right it is the average in this scenario, but you have to be aware of the Current consumption during
device initialization, the modules that you will have enabled WIFI, etc. 

Regards,

Mario

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