According to the datasheet for the MPX53DP differential pressure sensor, the output voltage should be in the range of 20-80mV, proportional to the differential pressure.
I have set it up with a 3.3v power supply and was expecting to need an amplifying circuit but at a differential pressure of 0 (both nozzles are open), the output voltage is 1.75V. However, when I apply pressure, the voltage rises as expected in the datasheet.
So my question is this: How do I have an offset of 1.75V when it should be 0.02V?
Thank you in advance for your help
Jordan
Solved! Go to Solution.
Hi Jordan,
I believe you are measuring the voltage on either +Vout or -Vout output with respect to GND. However, you should measure the differential voltage between +Vout or -Vout. At the maximum differential pressure of 50kPa, the differential output voltage between +Vout or -Vout should be around 60mV.
I hope it helps. If I misunderstood your question or if you have further questions, please let me know.
Best regards,
Tomas
Hi Jordan,
I believe you are measuring the voltage on either +Vout or -Vout output with respect to GND. However, you should measure the differential voltage between +Vout or -Vout. At the maximum differential pressure of 50kPa, the differential output voltage between +Vout or -Vout should be around 60mV.
I hope it helps. If I misunderstood your question or if you have further questions, please let me know.
Best regards,
Tomas
Thank you so much Tomas - It seems so simple once you put it like that.
I will have to use a differential op-amp then :smileyhappy: