problems with sqrt() function

[Franklin]

I am trying to do the following calculation

              location[3] = isqrt((dist_3^2)-((location[1])^2)-(location[2])^2);

and I get

Error C1826: Integer-expression expected

Error C5002: Illegal type

Error C1829: +- Incompatible types

among others.

"location" is a double, and "dist_3" is an int.

I put a line, #include "math.h" at the top of my code...

[kef]

---

              location[3] = isqrt((dist_3^2)-((location[1])^2)-(location[2])^2);

---

XORing with double is something :smileyhappy:

Regards

Message Edited by kef on 2008-05-30 11:51 PM

[CompilerGuru]

To compute the square, multiply it with itself,
dist_3^2 does toggle the second last bit :smileyhappy:.
So try dist_3*dist_3 instead.

Daniel

[Lundin]

There is also the pow() function which works for float numbers.