Hello All,
I am new on Codewarrior and in my current project(9S08PA8) I need a 32 bits variable to receive the result of a math operation.
This variable will receive a value from a single multiply operation(eg. ADC_result x 87).
Below a snippet of my code:
uint8_t Mult=87;
uint32_t temp=0;
.
.
.
temp=(uint32_t)(adc_result0*Mult);
What happens is that if the value of adc_result0 is below or equal to 753 (the result ocupy only 2 bytes) everything is ok, but if the adc_result0 is higher than 753 (the result does not fill in 2 bytes) the compiler casts the result to 2 bytes. My question is can the HCS08 compiler operate in 32 bits variables? If not, what workaround can I use to solve this problem? (I tried to declare the variable as dword, unsigned long, long, without success).
Thanks,
已解决! 转到解答。
This is how C works. 16 bits operation gives 16 bits result. You need to implicitly cast at least one of multipliers to 32 bits to get 32 bits product.
temp=(uint32_t)( (uint32_t)adc_result0*Mult);
Regards,
Edward
This is how C works. 16 bits operation gives 16 bits result. You need to implicitly cast at least one of multipliers to 32 bits to get 32 bits product.
temp=(uint32_t)( (uint32_t)adc_result0*Mult);
Regards,
Edward