Write HEX to LCD

[mariaotero]

Hello, i'm kinda new in all this world. So, i'm trying to display like decimal an hexadecimal value into a LCD 16x2 display.

I know the i need to write it in ASCII, but my problem is the i can't figure it out how to split that value into 4 or 5 bytes, for example:
0x270F = 0x39 0x39 0x39 0x39 (9999)
0xFFFF = 0x36 0x35 0x35 0x33 0x35 (65535).

Don't even know how to search for what i'm looking . Some guidance would be useful.

Thank you . (sorry for my bad english not my native language

PD: Working with S08AW32 Relocatable ASM in CodeWarrior 10.2

[mariaotero · Accepted solution]

This is how i solved, any advice or critic would be nice :smileyhappy:.

;////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////

DataRAM DS 2

Centena ds 1

Decena ds 1

Unidad ds 1

Stack ds 1

;*************************************

;DataRAM = Any value between 0 and 999

;*************************************

LDHX DataRAM

CPHX #100

BLO MENOR

BHI MAYOR

MENOR LDA DataRAM+1

LDHX #10

DIV

STA Decena

ldhx           #10

MUL

ldhx           DataRAM

JSR srAIXdc

stx          Unidad

Jsr srBCD

RTS

MAYOR            CPHX #255

BHI MAYOR2

LDA DataRAM+1

LDHX #100

DIV

rtMY1 STA Centena

LDHX #100

MUL

LDHX DataRAM

jsr srAIXct

STX Stack

LDA Stack

LDHX #10

DIV

STA Decena

ldhx           #10

MUL

ldx          Stack

JSR srAIXdc

stx          Unidad

Jsr srBCD

RTS

MAYOR2 LDA DataRAM+1

LDHX DataRAM+0

LDX #100

DIV

JMP rtMY1

;*************************************

;*************SubRoutines*************

;*************************************

srAIXct:           LDA Centena

lpAIct aix #-100

deca

cmp #0

bne lpAIct

RTS

srAIXdc:           LDA Decena

lpAIdc aix #-10

deca

cmp #0

bne lpAIdc

RTS

srBCD: LDA #$89

JSR LCDi

LDA Centena

ADD #$30

JSR LCDw

LDA Decena

ADD #$30

JSR LCDw

LDA Unidad

ADD #$30

JSR LCDw

RTS

;////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////

[mariaotero]

Sorry for not saying, but i don't know C. I can read it, but i can't code in that language.

Okay, i will try to make a project with C and ASM to see if i can debug it, to get the ASM code.

Any idea of how can i search for what i'm looking?

Thank you for the answers :smileyhappy:.

[ZhangJennie]

Hi,

I am not assembly code expert, but if use C, we can implement the code this way: thus D0,D1,D2,D3 is 9,9,9,9. can it help you?

//////////////////////////////////////////////////////////////////////

int ASCII(int data)

void main(void) {

volatile  int data=0x270F;

volatile  int D0,D1,D2,D3;

D0 = ASCII(data%10);

D1 = ASCII((data%100-data%10)/10);

D2 = ASCII((data%1000-data%100)/100);

D3 = ASCII((data%10000-data%1000)/1000);

}

int ASCII(int data) {

if ( (data<=9) && (data>=0))

   return (data + '0');

else

   return 1;

}

///////////////////////////////////////////////////

Have a great day,
Zhang Jun

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[StenS]

The easiest (but absolutely not the most efficient) way is to use the sprintf-function:

char buff[6];

unsigned int num;

sprintf(buff, "%u", num);

After this the number will be as a null-terminated string (1..5 characters plus the terminating \0) in buff. By adding formating specifications you can affect how the number is converted.

Sten