QG8 internal pullup = 150uA???

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QG8 internal pullup = 150uA???

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UtopiaTim
Contributor III
Hi Folks,
 
I must be missing something - I'm working on reducing current consumption on a
battery device, and it's drawing about 150 uA more than it should in STOP3 mode.
 
I narrowed it down to when I select an internal pullup with PTAPE.  If no pullup is
selected, the current is basically nothing.  With it, it is 150uA.  It is PTA1, and I'm
using it as a keyboard interrupt.
 
If I put an external pullup on it (for a switch), the circuit works fine, and there
is no extra current.
 
Ideas?
 
Thanks,

Tim
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admin
Specialist II
You wouldn't happen to have the KBEDG1 bit set, do you? If set this would make the internal resistor a pulldown rather than a pullup. Not having seen your circuit I don't know if this is relevant or not.
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UtopiaTim
Contributor III
Hi Wingsy,
 
Checked, and the bit is clear - set for falling edge.
 
Tim
 
 
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Lundin
Senior Contributor IV
150uA seems resonable to me. 3.3V / 150u = 22kOhm.

I might have misunderstood the problem, but how exactly do you expect a pull-up to work with 0A current through it?
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peg
Senior Contributor IV
Ah, I presume he meant with the switch open.
With it closed you should see something like this (probably a fair bit less)
A pullup will work with virtually no current when it is pulling up a CMOS input gate.
A Utopian one:smileyvery-happy:

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UtopiaTim
Contributor III
Cute! :smileyhappy:
 
Yes, it's with the switch open.
 
I'm not worried about the current when the switch is closed (it's minimal
compared to what the rest of the circuit is drawing).
 
Guess I'll put a pullup on the board, & if I figure it out before production,
it'll just be a no populate.
 
Thanks,
 
Tim
 
 
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