Hi, I am working on calculating the power dissipation of MCIMX286CVM4B based on the current consumption on each of the power rail (See below) . All of the power source is from the internal DC/DC buck regulator of IMX286 without any battery connected. With the help of a software to measure the junction temperature, the software reads out 60°C at 24°C ambient. Doing the math with 36°C/W of thermal resistance considering 6-layer PCB, the total power dissipated is 1.0 Watt. The 5V power source to internal buck regulators measures 0.204 Amps giving 1.02 Watt of input power, this is what confuses me. How can power dissipation be almost equal to consumption. Am I doing anything incorrect?

VDDIO(3.3V) = 0.0215 Amps ---> 0.0709 Watt

VDDA (1.8V) = 0.0903 Amps ---> 0.1625 Watt

VDDD (1.2V) = 0.252 Amps ---> 0.3027 Watt

Total -----------------------------------> 0.53625 Watt ( consumption )

Since I have the above consumption data, the 5V source measures 1.02 Watt including dissipation of lower voltage power rails. Therefore the dissipation should be 1.02 - 0.53625 = 0.4837 Watt of power dissipation resulting in 42.4°C of junction temperature, which is not the case.

The processor is exposed to air at 24°C ambient and on a 6-layer PCB.

Please advise. your inputs on this is much appreciated.

Thank you.

Best regards,

Rakshith Manjunath

Hi Rakshith

right, power dissipation is almost equal to consumption since

most current from these supplies is consumed by i.MX28 internally.

For example VDDD current is consumed by i.MX28 core.

Power supplies usage is described in AN4199

Using the i.MX28 Power Management Unit and Battery ChargerTypical i.MX28 VDDIO,VDDA,VDDD consumption can be found in Table 12

i.MX28 Applications Processors for Consumer ProductsAlso one can take into account temperature sensor accuracy Question, i.MX28 Internal Temperature sensisng

and dcdc efficiency (about 85%).

Best regards

igor

-----------------------------------------------------------------------------------------------------------------------

Note: If this post answers your question, please click the Correct Answer button. Thank you!

-----------------------------------------------------------------------------------------------------------------------