A LOCKUP reset will occur in the partition of MKE15Z256VLH7

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A LOCKUP reset will occur in the partition of MKE15Z256VLH7

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wanglanjun
Contributor II

Dear all,
I want to configure FlexNVM as EEPROM in MKE15Z256VLH7. First, I need to partition it. I use the FLEXNVM_ProgramPartition function(the API of SDK 2.6.0) to partition. If I call this function in the interrupt handler, everything works fine! But if I call this function in application code, Once excutes allFtfxRunCommand function of fsl_ftfx_controller.c file, MKE15Z256VLH7 will cause LOCKUP reset. it failed.Does anyone know why?
How long does the partition take?
Can there be an interruption during the execution of the partition?
What is the timing requirement for the execution partition?

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FelipeGarcia
NXP Employee
NXP Employee

 Hi,

 

You cannot execute interrupts while you are handling with Flash, if your interrupts code is running from Flash then it is likely that you have this unpredicted behavior. If you do not run the interrupts from RAM then you must disable them.

 

Best regards,
Felipe

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FelipeGarcia
NXP Employee
NXP Employee

Hello,

 

Sorry for my late reply.

 

I highly recommend you to check our flexnvm_eeprom example of the SDK. There you can have a better idea on how and when to use FLEXNVM_ProgramPartition API.

 

You can download the latest version of the SDK from the following link.

Welcome | MCUXpresso SDK Builder  

 
Have a great day,
Felipe

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wanglanjun
Contributor II

yes, i really refer to the demo example before, This example only enables UART receive interrupt. When the partition is executed, there is no interruption. In fact, I can also succeed if I disable the global interrupt. But in my application, sometimes it is not allowed to disable global interrupts. Today I tested it again using the demo example. I have added a system tick timer and the timeout was 1 millisecond, Now MKE15Z256VLH7 will also generate a LOCKUP reset. So I guess, the reason should be related to the interruption too fast. But I don't know under what circumstances a LOCKUP reset will occur.

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FelipeGarcia
NXP Employee
NXP Employee

 Hi,

 

You cannot execute interrupts while you are handling with Flash, if your interrupts code is running from Flash then it is likely that you have this unpredicted behavior. If you do not run the interrupts from RAM then you must disable them.

 

Best regards,
Felipe

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wanglanjun
Contributor II

Ok,I see, I think maybe the main reason is vector table which is in flash, I donot remap it to RAM, if there is a interrupter, the code will jump to there, and than generate a LOCKUP reset.

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