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ADC0_CH7 and ADC0_CH8 triggle dma request question in mpc574x

Question asked by 大大许 on Nov 5, 2017
Latest reply on Nov 19, 2017 by 大大许

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Hi dear,

I have some question about ADC0_CH7 and ADC0_CH8 triggle dma request question in mpc574x. In my test,I try using ADC0_Ch7 and ADC0_CH8 EOC condition to triggle DAM transfer,pushing ADC0CH7 and ADC0CH8 CDR regist's result to indicate data buffer. But in my test, I find only one channel result is true ,other channel result in bad data. How should i change my configure to make ADC0_CH7 and CH8 transfer data is right. DMA use fix_prio and ADC0_CH7 prio == 7, ADC0_CH8 prio == 8

follow is my configure

ADC_0.DMAR0.B.DMA8 = 1;
ADC_0.DMAR0.B.DMA7 = 1;
ADC_0.DMAE.B.DCLR = 0;
ADC_0.DMAE.B.DMAEN = 1;

DMA_0.CR.B.CX = 0;      //normal operate mode
DMA_0.CR.B.ECX = 0;
DMA_0.CR.B.GRP1PRI = 1;    //Fixed priority arbitration
DMA_0.CR.B.GRP0PRI = 0;
DMA_0.CR.B.EMLM = 1;      //enable minor loop mapping and disable offset
DMA_0.CR.B.CLM = 0;
DMA_0.CR.B.HALT = 0;
DMA_0.CR.B.HOE = 0;
DMA_0.CR.B.ERGA = 0;
DMA_0.CR.B.ERCA = 0;
DMA_0.CR.B.EDBG = 0;

DMAMUX_0.CHCFG[4].B.TRIG = 0; //设置adc0_ch8的dma通道
DMAMUX_0.CHCFG[4].B.SOURCE = 0x12;
DMAMUX_0.CHCFG[4].B.ENBL = 1;

DMA_0.ERQ.B.ERQ4 = 1; //open hardware request

DMA_0.TCD[4].SADDR.R = 0xFBE00120;   //ADC0_CH8_CDR_ADD
    DMA_0.TCD[4].ATTR.B.SMOD = 0;
    DMA_0.TCD[4].ATTR.B.SSIZE = 2;       //uint16
  DMA_0.TCD[4].SOFF.R = 0;
DMA_0.TCD[4].SLAST.R = 0;

DMA_0.TCD[4].DADDR.R =(uint32_t) adc0Ch8Data;
DMA_0.TCD[4].ATTR.B.DMOD = 0;
DMA_0.TCD[4].ATTR.B.DSIZE = 2;
DMA_0.TCD[4].DOFF.R = 4;
DMA_0.TCD[4].DLASTSGA.R = -80; //只有在major loop 完成以后才执行这个步骤

DMA_0.TCD[4].NBYTES.MLOFFNO.B.SMLOE = 0;   //minor loop enable and link-to-link disable
DMA_0.TCD[4].NBYTES.MLOFFNO.B.DMLOE = 0;   //minor loop offset is applied to the SADDR
DMA_0.TCD[4].NBYTES.MLOFFNO.B.NBYTES = 4;           //minor loop cnt
DMA_0.TCD[4].BITER.ELINKNO.B.ELINK = 0;
DMA_0.TCD[4].BITER.ELINKNO.B.BITER = 20;
DMA_0.TCD[4].CITER.ELINKNO.B.ELINK = 0;
DMA_0.TCD[4].CITER.ELINKNO.B.CITER = 20;
DMA_0.TCD[4].CSR.B.BWC = 0;
DMA_0.TCD[4].CSR.B.MAJORLINKCH = 0;
DMA_0.TCD[4].CSR.B.ACTIVE = 0;
DMA_0.TCD[4].CSR.B.DONE = 0;
DMA_0.TCD[4].CSR.B.MAJORELINK = 0;
DMA_0.TCD[4].CSR.B.ESG = 0;
DMA_0.TCD[4].CSR.B.INTHALF = 0;
DMA_0.TCD[4].CSR.B.INTMAJOR = 1;
DMA_0.TCD[4].CSR.B.START = 0;

DMAMUX_0.CHCFG[5].B.TRIG = 0;             //设置adc0_ch7的dma通道
DMAMUX_0.CHCFG[5].B.SOURCE = 0x12;
DMAMUX_0.CHCFG[5].B.ENBL = 1;
DMA_0.ERQ.B.ERQ5 = 1; //open hardware request
DMA_0.TCD[5].SADDR.R = 0xFBE0011C;   //ADC0_CH7_CDR_ADD
    DMA_0.TCD[5].ATTR.B.SMOD = 0;
    DMA_0.TCD[5].ATTR.B.SSIZE = 2;       //uint16
  DMA_0.TCD[5].SOFF.R = 0;
DMA_0.TCD[5].SLAST.R = 0;
DMA_0.TCD[5].DADDR.R =(uint32_t) adc0Ch7Data;
DMA_0.TCD[5].ATTR.B.DMOD = 0;
DMA_0.TCD[5].ATTR.B.DSIZE = 2;
DMA_0.TCD[5].DOFF.R = 4;
DMA_0.TCD[5].DLASTSGA.R = -80;       //只有在major loop 完成以后才执行这个步骤
DMA_0.TCD[5].NBYTES.MLOFFNO.B.SMLOE = 0;   //minor loop enable and link-to-link disable
DMA_0.TCD[5].NBYTES.MLOFFNO.B.DMLOE = 0;   //minor loop offset is applied to the SADDR
DMA_0.TCD[5].NBYTES.MLOFFNO.B.NBYTES = 4;           //minor loop cnt
DMA_0.TCD[5].BITER.ELINKNO.B.ELINK = 0;
DMA_0.TCD[5].BITER.ELINKNO.B.BITER = 20;
DMA_0.TCD[5].CITER.ELINKNO.B.ELINK = 0;
DMA_0.TCD[5].CITER.ELINKNO.B.CITER = 20;
DMA_0.TCD[5].CSR.B.BWC = 0;
DMA_0.TCD[5].CSR.B.MAJORLINKCH = 0;
DMA_0.TCD[5].CSR.B.ACTIVE = 0;
DMA_0.TCD[5].CSR.B.DONE = 0;
DMA_0.TCD[5].CSR.B.MAJORELINK = 0;
DMA_0.TCD[5].CSR.B.ESG = 0;
DMA_0.TCD[5].CSR.B.INTHALF = 0;
DMA_0.TCD[5].CSR.B.INTMAJOR = 1;
DMA_0.TCD[5].CSR.B.START = 0;

Thanks!

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David Tosenovjan

Nov 6, 2017 1:53 AM

Hi, it'll be because the is only one DMA input trigger from ADC_0.

DMA module is not capable to distinguish which ADC channel triggers the DMA request as you have the same source assigned to both TCDs, thus both conversions triggers both DMA tranfers.

You should set up only one TCD for ADC_0 conversion.

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大大许 @ David Tosenovjan on Nov 6, 2017 4:37 AM

Hello ,

I'am sorry that I don't understand you mean. In other words:

ADC_0 is only one channel have dma data transfer function.

if DMA support ADC0_CH7 and ADC0_Ch8 triggle DMA transfer function after each channel create an eoc condition,How should i change my code.

thanks .

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大大许 Nov 6, 2017 8:13 PM

Hello,

setting up only one TCD for ADC_0 conversion,it means that just only one channel support dma transfer for each adc.

I maybe have adc0_ch7, adc0_ch8,adc1_ch0,adc1_ch1 channel to detection voltage in the car,each adc channel will have dma transfer function,how I should change my code.

Thanks.

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David Tosenovjan

@ 大大许 on Nov 7, 2017 12:27 AM

You can set up conversion for channel 7 and 8 and after conversion of chnl 8, perform two DMA transfers for reading of both results.

1 person found this helpful

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大大许 @ David Tosenovjan on Nov 7, 2017 4:59 AM

Hello ,

Thanks for you reply, I try to set one tcd for ADC0_ch7 and adc0_ch8,but i have meeting a problem ,sources address and destinate address just only one,so i don't how to allocate two adc channel address.

setting up conversion for channel 7 and 8 and after conversion of chnl 8, perform two DMA transfers for reading of both results, I'm sorry that i don't how to operate,could you post an example ?

Thanks.

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David Tosenovjan

@ 大大许 on Nov 8, 2017 12:55 AM

You can simply set up DMA minor loop consisting of two transfers, thus by proper NBYTES setting and offsets. It should not be difficult.

Also you may link two TCDs together, that's the option as well.

1 person found this helpful

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大大许 @ David Tosenovjan on Nov 8, 2017 1:39 AM

Hello ,

Thanks for you reply.

Can I understand that ADC0CH7 is source address and just one destination buffer.

In the one minor loop

first dma read CH7_CDR data , sending data to specific destination buffer, then source address and destination address add offset value.

second source address equal Ch8_CDR regist's address ,sending Ch8_CDR's data to next destination address.

then source and destination address return to initial value.

finally , it repeat this loop over and over again.

Thanks.

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大大许 @ David Tosenovjan on Nov 19, 2017 7:16 AM

Hello ,

I have some question of adc0_ch7 and adc0-ch8 inject conversion finish to triggle dma transfer,In adc module just set adc8's dma ,

adc0_CH7 and adc0_ch8 register data through dma transfer a data buffer when JECH flag is setting.

in my configure, dma using single dma transfer,source address is adc0_ch7's address,an minor transfer byte == 8,I think it can make adc0_ch7 and adc0_ch8 data transfer to data buffer.

I find data buffer[n] have adc0_Ch7 data , but data buffer[n+1] is initial value,it not change.

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8 Replies

David Tosenovjan Nov 6, 2017 1:53 AM
Mark Correct
Correct Answer
Hi, it'll be because the is only one DMA input trigger from ADC_0.
DMA module is not capable to distinguish which ADC channel triggers the DMA request as you have the same source assigned to both TCDs, thus both conversions triggers both DMA tranfers.
You should set up only one TCD for ADC_0 conversion.
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- 大大许 @ David Tosenovjan on Nov 6, 2017 4:37 AM
  Mark Correct
  Correct Answer
  Hello ,
  I'am sorry that I don't understand you mean. In other words:
  ADC_0 is only one channel have dma data transfer function.
  if DMA support ADC0_CH7 and ADC0_Ch8 triggle DMA transfer function after each channel create an eoc condition,How should i change my code.
  thanks .
  Like • Show 0 Likes0
  Actions
大大许 Nov 6, 2017 8:13 PM
Mark Correct
Correct Answer
Hello,
setting up only one TCD for ADC_0 conversion,it means that just only one channel support dma transfer for each adc.
I maybe have adc0_ch7, adc0_ch8,adc1_ch0,adc1_ch1 channel to detection voltage in the car,each adc channel will have dma transfer function,how I should change my code.
Thanks.
Like • Show 0 Likes0
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- David Tosenovjan @ 大大许 on Nov 7, 2017 12:27 AM
  Mark Correct
  Correct Answer
  You can set up conversion for channel 7 and 8 and after conversion of chnl 8, perform two DMA transfers for reading of both results.
  1 person found this helpful
  Like • Show 1 Like1
  Actions
  - 大大许 @ David Tosenovjan on Nov 7, 2017 4:59 AM
    Mark Correct
    Correct Answer
    Hello ,
    Thanks for you reply, I try to set one tcd for ADC0_ch7 and adc0_ch8,but i have meeting a problem ,sources address and destinate address just only one,so i don't how to allocate two adc channel address.
    setting up conversion for channel 7 and 8 and after conversion of chnl 8, perform two DMA transfers for reading of both results, I'm sorry that i don't how to operate,could you post an example ?
    Thanks.
    Like • Show 0 Likes0
    Actions
    - David Tosenovjan @ 大大许 on Nov 8, 2017 12:55 AM
      Mark Correct
      Correct Answer
      You can simply set up DMA minor loop consisting of two transfers, thus by proper NBYTES setting and offsets. It should not be difficult.
      Also you may link two TCDs together, that's the option as well.
      1 person found this helpful
      Like • Show 1 Like1
      Actions
      - 大大许 @ David Tosenovjan on Nov 8, 2017 1:39 AM
        Mark Correct
        Correct Answer
        Hello ,
        Thanks for you reply.
        Can I understand that ADC0CH7 is source address and just one destination buffer.
        In the one minor loop
        first dma read CH7_CDR data , sending data to specific destination buffer, then source address and destination address add offset value.
        second source address equal Ch8_CDR regist's address ,sending Ch8_CDR's data to next destination address.
        then source and destination address return to initial value.
        finally , it repeat this loop over and over again.
        Thanks.
        
        Like • Show 0 Likes0
        Actions
      - 大大许 @ David Tosenovjan on Nov 19, 2017 7:16 AM
        Mark Correct
        Correct Answer
        Hello ,
        I have some question of adc0_ch7 and adc0-ch8 inject conversion finish to triggle dma transfer,In adc module just set adc8's dma ,
        adc0_CH7 and adc0_ch8 register data through dma transfer a data buffer when JECH flag is setting.
        in my configure, dma using single dma transfer,source address is adc0_ch7's address,an minor transfer byte == 8,I think it can make adc0_ch7 and adc0_ch8 data transfer to data buffer.
        I find data buffer[n] have adc0_Ch7 data , but data buffer[n+1] is initial value,it not change.
        Like • Show 0 Likes0
        Actions

ADC0_CH7 and ADC0_CH8 triggle dma request question in mpc574x

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