Hello Team,
From machine exception ( interrupt vector 5 ) handler we are jumping to reset vector address 0x00FFFFFC.
this will again generate the machine exception interrupt for number of time and application control is stuck in it.
Application control is not jumping to address 0x00FFFFFC.
Requesting help for the same.
Thanks & Regards,
Charudatta
Hello Team,
I am handling machine exception in software as shown below.
interrupt 5 void ECC_ISR(void)
{
/* Log the DTC */
__asm(JMP 0x00FFFFFC ); /* I am not able to jump to reset vector */
}
Vector 0 is mapped to _Startup
I believe something gone wrong with startup stack initialization as shown below
_EXTERN_C void _Startup(void) {
__asm {
LD S, #__SEG_END_SSTACK-1 /* initialize SP */
#ifdef __ALIGN_STACK_OPT__
TFR S, D6 /* align SP to 4*/
AND D6, #-4
TFR D6, S
#endif
}
DoZeroOut();
DoCopyDown();
#ifdef __cplusplus
__static_init();
#endif
main();
}
static void DoZeroOut(void) {
__asm {
LD D6, _startupData.nofZeroOuts
BEQ end /* nothing to do */
LD X, _startupData.pZeroOut
zeroOutLoop:
LD Y, (0,X) /* X points to the first range */
LD D7, (3,X) /* D7 holds size */
doZeroOut:
CLR.b (Y+)
DBNE D7, doZeroOut
LEA X, (7,X)
DBNE D6, zeroOutLoop
end:
}
}
static void DoCopyDown(void) {
__asm {
LD Y, _startupData.toCopyDownBeg
BEQ end /* the pointer is NULL */
nextItemLoop:
LD D6, (Y+) /* load the size */
BEQ end
LD X, (Y+) /* load the destination */
copyLoop:
MOV.b (Y+), (X+) /* copy the data */
DBNE D6, copyLoop
BRA nextItemLoop
end:
}
}
In Machine exception handler I am not able to jump to reset vector address 0x00FFFFFC .
How I can make it work ?
Please suggest.
Thank You very much.
Best Regards,
charudatta
Hello,
First, S12Z has a 16-bit CPU so it takes only 16-bit wide addresses. So this is probably the reason you get another machine exception.
The MCU goes through the reset vector at the end of Reset sequence, it is an entry point for an application.
Startup() function (see starts12z.c) is stored at the reset vector address.
So you can call the function and then the application will go through initialization.
// declaration
extern _Startup();
// jump to the address stored in the reset vector
_Startup();
But this will not restart the MCU.
There are only five reset sources. See Table 1-11 (Reset Sources and Vector Locations).
There are two possible options:
You can force COP reset
CPMUCOP = 0x01; // Initialize COP watchdog, unless it is already initialized.
// Note: CPMUCOP is write-once register
CPMUARMCOP = 0x00; // Write any value except 0x55 or 0xAA cause MCU reset
or you can use a GPIO pin connected to the reset pin externally.
In the machine exception, you can set it as output and pull the reset pin down.
Regards,
Daniel
Hello Daniel,
At this time we can not change the hardware design.
cop reset is not working for us due to some boot loader and application sync issue.
Is there any way to jump on reset vector address 0x00FFFFFC from application. ?
Thanks & Regards,
Charudatta
Hello Charudatta,
Two things:
So, in order to jump to the program-start, change your code to this:
__asm(JMP [0xFFFFFD]);
HTH,
MJW
Hello,
I’m not sure I understand.
In general, a machine exception is triggered upon an illegal memory access or due to a double-bit ECC error. It is not possible to return to the application and the MCU recovers through the reset.
Please check MMCEC registers which hold information about the cause of the machine exception.
Regards,
Daniel