In the Hardware Development Guide for i.MX7Dual
and 7Solo Applications Processors, it say:
Because only resistors are used, LCD bus loads can
cause current drain, leading to higher (false) supply
current measurements. Each LCD boot signal should
connect to a series resistor to isolate the bus from the
resistors and/or switchers; see Figure 1. Each
configured LCD boot signal sees either a 14.7 kΩ
pulldown or a 4.7 kΩ pullup. For each switch-enabled
pulled-up signal, the supply is presented with a 10 kΩ
current load.
An alternate approach using buffers is implemented in
the SABRE-SD development board design. Either of
these implementations is acceptable.
I want to simplify schematic, can 14.7 kΩ change to 10 kΩ
I have only three boot configuration, so it change to this
Is that right ?
