I have K60 Tower board: MK60FN1M0VLQ12.
In the reference manual, 184.108.40.206 Interrupt priority levels, and table Table 3-5. Interrupt vector assignments show the registers for each interrput. For example:
0x0000_013C 79 63 1 15 FTM1 Single interrupt vector for all sources
If I want to set the interrupt with PRIORITY 1:
I shall use register NVICIPR15, and
NVICIPR15 = 0x01;
Is this correct?
But the code generated by PE wizard:
NVICIP63 = NVIC_IP_PRI63(0x80);
/* NVICISER1: SETENA|=0x80000000 */
NVICISER1 |= NVIC_ISER_SETENA(0x80000000);
FTM1_SC |= FTM_SC_TOIE_MASK;
_int_install_isr(LDD_ivIndex_INT_FTM1, FC1_OnOverflow, NULL );
Why use NVICIP63 = NVIC_IP_PRI63(0x80); ?
what means to 0x80?
IPR registers contains 4 bits as stated in the section 220.127.116.11 Interrupt priority levels.
I am a little confused. What are priority levels (0-15 with 0 as highest priority?) or priorities from 0 - 0xFF ?