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Processor Expert External Interrupt Component

Question asked by Richard Fox on Aug 15, 2016
Latest reply on Aug 19, 2016 by Richard Fox

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The processor I am using is the MK22FN256VLH12. A GPIO bit in a Port is configured

as an Input which will interrupt on both edges of the signal.The ExtInt component is

used to configure the interrupts. An ExtInt_Ldd has been built with an Initialization

function, the Interrupt handler, and the GetVal function. I use the GetVal to determine

which edge caused the interrupt.

First the Initialization function in ExtInt_LDD is never called, is this correct?

My main problem is the first time that an interrupt is generated my ISR is entered

at the function's entry point. However, the next interrupt results in the ISR being entered

in the middle of the function.Is this a result of the data structure not being initialized?

What can I do to make this work correctly?

I must have had a brain freeze. What I need to do is have 1 ISR which checks which pin caused

the interrupt and processes accordingly. I apologize for wasted time.

SORRY - The problem description is incorrect. My reply to Robin describes the problem that I am having.

I was relying on Breakpoints that did not trigger.

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Robin_Shen

Aug 16, 2016 1:12 AM

Hi Richard,

The initialization function is called in my project.(See the attached image)

I'm not very clear about: "My main problem is the first time that an interrupt is generated my ISR is entered at the function's entry point. However, the next interrupt results in the ISR being entered in the middle of the function."

Could you please attach these two images?

Best Regards,

Robin

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Richard Fox @ Robin_Shen on Aug 16, 2016 6:42 AM

Robin,

Sorry, the problem description in my post is incorrect. I went through the generated code this

morning, and see what is actually happening.

I am using 2 GPIOs in Port B to determine if a switch has been pressed. The first GPIO is for

on row in the switch matrix. The second GPIO is for another row (a different set of switches).

I have both GPIOs configured to interrupt on both edges of the switch press. The two GPIOs

should be independent. The first GPIO uses ExtLdd2, while the second one uses ExtLdd3.

I expected that there would be two distinct ISRs for the Ports. However, the CPU component

has set up both of the external interrupt components as one.

PE_ISR(Cpu_ivINT_PORTB)

{

ExtIntLdd2_Interrupt();

ExtIntLdd3_Interrupt();

}

So the first of my ISRs falls into the second ISR.

Somehow I need to have Processor Expert assign two different interrupt vectors for the two

components.Probably something that I misconfigured.

Regards,

Richard

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Robin_Shen

@ Richard Fox on Aug 17, 2016 12:38 AM

Hi Richard,

All Ports have their own ISR(interrupt vector). If you need to have Processor Expert assign two different interrupt vectors for the two components, please use two different Ports.(for example:one GPIO in Port B and the other GPIO in Port C)

If you using 2 GPIOs in Port B, the code will "Check the pin interrupt flag of the shared interrupt" to determine which switch caused the PE_ISR(Cpu_ivINT_PORTB).

Best Regards,

Robin

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Richard Fox @ Robin_Shen on Aug 17, 2016 5:14 AM

Robin,

Thanks for your input. I have the code working. I just needed to

understand

how the generated code functioned.

Dick Fox

Firmware Engineer

NATIONAL CONTROLS CORPORATION BUSINESS UNIT

INSTRUMENTATION AND SPECIALTY CONTROLS DIVISION

1725 Western Dr | West Chicago, IL 60185 | http://www.ametekncc.com

Phone: (630)621-3118 | email: Dick Fox@ametek.com

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Robin_Shen

@ Richard Fox on Aug 18, 2016 8:02 PM

Hi Richard,

Which "generated code" do you want to understand? Do you mean PE_ISR(Cpu_ivINT_PORTB)?

The ISF bit in PORTx_PCRn is used to determine which GPIO caused the interrupt of Port B. You can see the code(pink line) in attached image at my last reply. If the interrupt is caused by ExtIntLdd2_Interrupt, the code will still run into ExtIntLdd1_Interrupt to check the pin interrupt flag(ISF of PORTx_PCRn) first. And then run into ExtIntLdd2_Interrupt to chenk the the second pin interrupt flag.

If you still need to have Processor Expert assign two different interrupt vectors for the two components? The Port B has only one interrupt vector, all the GPIOs in Port B share this interrupt vector. So if you still need two different interrupt vectors for the two components, you need to use two GPIOs in different Port.

Best Regards,

Robin

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Richard Fox @ Robin_Shen on Aug 19, 2016 5:36 AM

Robin,

I don't need help understanding the code. After I looked at the

code I understood how it worked. My program is working. Thanks

for your assistance.

Dick Fox

Firmware Engineer

NATIONAL CONTROLS CORPORATION BUSINESS UNIT

INSTRUMENTATION AND SPECIALTY CONTROLS DIVISION

1725 Western Dr | West Chicago, IL 60185 | http://www.ametekncc.com

Phone: (630)621-3118 | email: Dick Fox@ametek.com

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6 Replies

Robin_Shen Aug 16, 2016 1:12 AM
Mark Correct
Correct Answer
Hi Richard,
The initialization function is called in my project.(See the attached image)
I'm not very clear about: "My main problem is the first time that an interrupt is generated my ISR is entered at the function's entry point. However, the next interrupt results in the ISR being entered in the middle of the function."
Could you please attach these two images?

Best Regards,
Robin
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- Richard Fox @ Robin_Shen on Aug 16, 2016 6:42 AM
  Mark Correct
  Correct Answer
  Robin,
  
  Sorry, the problem description in my post is incorrect. I went through the generated code this
  morning, and see what is actually happening.
  
  I am using 2 GPIOs in Port B to determine if a switch has been pressed. The first GPIO is for
  on row in the switch matrix. The second GPIO is for another row (a different set of switches).
  I have both GPIOs configured to interrupt on both edges of the switch press. The two GPIOs
  should be independent. The first GPIO uses ExtLdd2, while the second one uses ExtLdd3.
  I expected that there would be two distinct ISRs for the Ports. However, the CPU component
  has set up both of the external interrupt components as one.
  
  PE_ISR(Cpu_ivINT_PORTB)
  {
  ExtIntLdd2_Interrupt();
  ExtIntLdd3_Interrupt();
  }
  So the first of my ISRs falls into the second ISR.
  
  Somehow I need to have Processor Expert assign two different interrupt vectors for the two
  components.Probably something that I misconfigured.
  
  Regards,
  
  Richard
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  - Robin_Shen @ Richard Fox on Aug 17, 2016 12:38 AM
    Mark Correct
    Correct Answer
    Hi Richard,
    All Ports have their own ISR(interrupt vector). If you need to have Processor Expert assign two different interrupt vectors for the two components, please use two different Ports.(for example:one GPIO in Port B and the other GPIO in Port C)
    
    If you using 2 GPIOs in Port B, the code will "Check the pin interrupt flag of the shared interrupt" to determine which switch caused the PE_ISR(Cpu_ivINT_PORTB).
    
    Best Regards,
    Robin
    
    -----------------------------------------------------------------------------------------------------------------------
    Note: If this post answers your question, please click the Correct Answer button. Thank you!
    -----------------------------------------------------------------------------------------------------------------------
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    - Richard Fox @ Robin_Shen on Aug 17, 2016 5:14 AM
      Mark Correct
      Correct Answer
      Robin,
      
      Thanks for your input. I have the code working. I just needed to
      understand
      how the generated code functioned.
      
      Dick Fox
      Firmware Engineer
      
      NATIONAL CONTROLS CORPORATION BUSINESS UNIT
      INSTRUMENTATION AND SPECIALTY CONTROLS DIVISION
      1725 Western Dr | West Chicago, IL 60185 | http://www.ametekncc.com
      Phone: (630)621-3118 | email: Dick Fox@ametek.com
      Like • Show 0 Likes0
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      - Robin_Shen @ Richard Fox on Aug 18, 2016 8:02 PM
        Mark Correct
        Correct Answer
        Hi Richard,
        Which "generated code" do you want to understand? Do you mean PE_ISR(Cpu_ivINT_PORTB)?
        The ISF bit in PORTx_PCRn is used to determine which GPIO caused the interrupt of Port B. You can see the code(pink line) in attached image at my last reply. If the interrupt is caused by ExtIntLdd2_Interrupt, the code will still run into ExtIntLdd1_Interrupt to check the pin interrupt flag(ISF of PORTx_PCRn) first. And then run into ExtIntLdd2_Interrupt to chenk the the second pin interrupt flag.
        
        If you still need to have Processor Expert assign two different interrupt vectors for the two components? The Port B has only one interrupt vector, all the GPIOs in Port B share this interrupt vector. So if you still need two different interrupt vectors for the two components, you need to use two GPIOs in different Port.
        
        Best Regards,
        Robin
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        Richard Fox @ Robin_Shen on Aug 19, 2016 5:36 AM
        Mark Correct
        Correct Answer
        Robin,
        
        I don't need help understanding the code. After I looked at the
        code I understood how it worked. My program is working. Thanks
        for your assistance.
        
        Dick Fox
        Firmware Engineer
        
        NATIONAL CONTROLS CORPORATION BUSINESS UNIT
        INSTRUMENTATION AND SPECIALTY CONTROLS DIVISION
        1725 Western Dr | West Chicago, IL 60185 | http://www.ametekncc.com
        Phone: (630)621-3118 | email: Dick Fox@ametek.com
        Like • Show 0 Likes0
        Actions

Processor Expert External Interrupt Component

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