imx6 mipi camera pixel image size

[viswanathreddy]

Hi All,

mxc_v4l2_capture.c file in below content what basis they hard coded .

     cam->v2f.fmt.pix.sizeimage = 352 * 288 * 3 / 2;    // expalin me this values what basis
    cam->v2f.fmt.pix.bytesperline = 288 * 3 / 2;
    cam->v2f.fmt.pix.width = 288;
    cam->v2f.fmt.pix.height = 352;

Crop bound width and height is 640*480 but how  v2f format width is 288 how ?

Would you please help me any one , I am beginner of the camera driver .

Thanks

Viswa 

[igorpadykov]

Hi Viswa

these calculations are for memory requirements, how many bytes

needed for one pixel. Also please check Table 37-2. Data Formats Supported By The

Camera Port i.MX6DQ Reference Manual

http://cache.freescale.com/files/32bit/doc/ref_manual/IMX6DQRM.pdf

and AN5305 MIPI–CSI2 Peripheral on i.MX6 MPUs

http://www.nxp.com/assets/documents/data/en/application-notes/AN5305.pdf 

Best regards
igor
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[viswanathreddy]

Hi Igor,

Thanks for your quick reply.

i verified the imx6DQRM.pd .

This for formula :

F = FH * FW * FPS * BI * DF

crop bound height 640

crop bound width 480

sorry I am not understanding,

if you possible, Would you please explain me in detail what basis they calculated

Thanks

Viswa