Hi,
I have a question about NAND timing delay calculation RDN_DELAY in GPMI_CTRL1 of i.MX6ULL reference manual.
There is a description of example in page 1379 -1380 of i.MX 6ULL Applications Processor Reference Manual, Rev. 1, 11/2017.
"For example, a NAND with tREAmax = 20 ns, tRPmin = 12 ns, and tRCmin = 25 ns
(read cycle time) may be programmed as follows:
• GPMICLK clock frequency: Consider 480/6 = 80 MHz which is 12.5 ns clock
period. This is too close to the minimum NAND spec if we program the data setup
and hold to 1 GPMICLK cycle. Consider 480/7=68.57 MHz which is 14.58 ns clock
period. With data setup and hold set to 1, we have a tRP of 14.58ns and a tRC of
29.16 ns (good margins).
• Since (tREA +4ns) is greater than tRP, required DELAY = tREA + 4ns - tRP = 20 +
4 - 14.58ns = 9.42 ns.
• GPMI_CTRL1[HALF_PERIOD] =, since GPMICLK period is ns. So
RP=GPMICLK period = ns.
• DELAY = GPMI_CTRL1[RDN_DELAY] x 0.125 x RP. 9.42 ns =
GPMI_CTRL1[RDN_DELAY] x 0.125 x ns. GPMI_CTRL1[RDN_DELAY] =
However, in the last two paragraph, some data are missing.
Is it correct below red bold numbers?
• GPMI_CTRL1[HALF_PERIOD] =0, since GPMICLK period is 14.58 ns. So
RP=GPMICLK period = 14.58 ns.
• DELAY = GPMI_CTRL1[RDN_DELAY] x 0.125 x RP.
9.42 ns =GPMI_CTRL1[RDN_DELAY] x 0.125 x 14.58 ns.
GPMI_CTRL1[RDN_DELAY] =5.169=[0101b]
Best Regards,
Sugiyama
Solved! Go to Solution.
Hello,
Your understanding is correct.
Have a great day,
Yuri.
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Hello,
Your understanding is correct.
Have a great day,
Yuri.
-------------------------------------------------------------------------------
Note:
- If this post answers your question, please click the "Mark Correct" button. Thank you!
- We are following threads for 7 weeks after the last post, later replies are ignored
Please open a new thread and refer to the closed one, if you have a related question at a later point in time.