Dear, @weidong_sun
can you show me how to sign a dtb?
is it a signed dtb required in bootz of u-boot in secure boot?
someone say yes, but i can sucess to "bootz zImage_signed - dtb_not_signed" in my uboot, and i find bootz only authenticate zImage and do not auth authenticate dtb. see below:
/*
* zImage booting support
*/
static int bootz_start(cmd_tbl_t *cmdtp, int flag, int argc,
char * const argv[], bootm_headers_t *images)
{
int ret;
ulong zi_start, zi_end;
ret = do_bootm_states(cmdtp, flag, argc, argv, BOOTM_STATE_START,
images, 1);
/* Setup Linux kernel zImage entry point */
if (!argc) {
images->ep = load_addr;
debug("* kernel: default image load address = 0x%08lx\n",
load_addr);
} else {
images->ep = simple_strtoul(argv[0], NULL, 16);
debug("* kernel: cmdline image address = 0x%08lx\n",
images->ep);
}
ret = bootz_setup(images->ep, &zi_start, &zi_end);
if (ret != 0)
return 1;
lmb_reserve(&images->lmb, images->ep, zi_end - zi_start);
/*
* Handle the BOOTM_STATE_FINDOTHER state ourselves as we do not
* have a header that provide this informaiton.
*/
if (bootm_find_images(flag, argc, argv))
return 1;
#ifdef CONFIG_SECURE_BOOT
extern uint32_t authenticate_image(
uint32_t ddr_start, uint32_t image_size);
if (authenticate_image(images->ep, zi_end - zi_start) == 0) {
printf("Authenticate zImage Fail, Please check\n");
return 1;
}
#endif
return 0;
}
if we need to authenticate dtb, does it mean that we need to add the corresponding code to authenticate dtb in bootz()?