Hi, we are working on a similar sensor (ours is OV13850, only RAW10 supported). We have set the test pattern and got a raw data image. As per the above reply, the raw 10 data is converted to 16 bits by IPU. We couldn't quite understand this.
Suppose, the sensor sends data (1010001011 - RAW 10 - 10 Bits); after the IPU, do we get [9:0, 9:4] which is [1010001011 101000 - 16 bits] == 0xA2 0xE8 ?
Could you please help to understand this?
Also as a RAW10 format is sent as 5 bytes for every four pixels, is there a way we could discard the last two bits and get 8 bit data?
Thanks!