Config issue of LPDDR2

キャンセル
次の結果を表示 
表示  限定  | 次の代わりに検索 
もしかして: 

Config issue of LPDDR2

ソリューションへジャンプ
1,263件の閲覧回数
david5icp
Contributor III

Hello,

We have a customer board use 32 bit LPDDR2 and use 2 chip select. We can get config by DDR calibration tool and run  "DDR Stess test" more than 2 hours. Verey things seems ok.

It's fail to use the table on my android project. But if I ignor "CS1" setting as below, the board can boot up to android.

How to config 32 bit lpddr2 and use 2 chip select ? Thanks!

// Channel0 : Configure DDR device:         

//CS0   

setmem /32 0x021b001c = 0x003F8030 // MRW: BA=0 CS=0 MR_ADDR=63 MR_OP=0

setmem /32 0x021b001c = 0xFF0A8030 // MRW: BA=0 CS=0 MR_ADDR=10 MR_OP=ff

setmem /32 0x021b001c = 0x82018030 // MRW: BA=0 CS=0 MR_ADDR=1  MR_OP=c2

setmem /32 0x021b001c = 0x06028030 // MRW: BA=0 CS=0 MR_ADDR=2  MR_OP=6. tcl=8, tcwl=4

setmem /32 0x021b001c = 0x01038030 // MRW: BA=0 CS=0 MR_ADDR=3  MR_OP=2.drive=240/6

//CS1   

//setmem /32 0x021b001c = 0x003F8038 // MRW: BA=0 CS=1 MR_ADDR=63 MR_OP=0

//setmem /32 0x021b001c = 0xFF0A8038 // MRW: BA=0 CS=1 MR_ADDR=10 MR_OP=ff

//setmem /32 0x021b001c = 0x82018038 // MRW: BA=0 CS=1 MR_ADDR=1  MR_OP=c2

//setmem /32 0x021b001c = 0x06028038 // MRW: BA=0 CS=1 MR_ADDR=2  MR_OP=6. tcl=8, tcwl=4

//setmem /32 0x021b001c = 0x01038038 // MRW: BA=0 CS=1 MR_ADDR=3  MR_OP=2.drive=240/6

BR.

David Wu

ラベル(3)
0 件の賞賛
返信
1 解決策
1,093件の閲覧回数
david5icp
Contributor III

Hello ~

It's working now. The problem caused by dcd_hdr and write_dcd_cmd. Please refer below:

dcd_hdr:               .word 0x404802D2 /* Tag=0xD2, Len=72*8 + 4 + 4 = 0x0248, Ver=0x40 */

write_dcd_cmd:    .word 0x044402CC /* Tag=0xCC, Len=72*8 + 4 = 0x0244, Param=0x04 */

BR.

David Wu

元の投稿で解決策を見る

1 返信
1,094件の閲覧回数
david5icp
Contributor III

Hello ~

It's working now. The problem caused by dcd_hdr and write_dcd_cmd. Please refer below:

dcd_hdr:               .word 0x404802D2 /* Tag=0xD2, Len=72*8 + 4 + 4 = 0x0248, Ver=0x40 */

write_dcd_cmd:    .word 0x044402CC /* Tag=0xCC, Len=72*8 + 4 = 0x0244, Param=0x04 */

BR.

David Wu