PCA9615 Termination

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PCA9615 Termination

596 次查看
henryy
Contributor IV

According to the datasheet, the output impedance is 100 Ohm differential. On page 9, it mentioned 'R2 is 120, R1 is 600, The parallel combination yields a termination of 100'. How this was calculated? Two R1s should be in series then parallel with R2. Then R1 should be 300 Ohm to yield a combination 100 Ohm. Did I miss anything? May I use R2=100Ohm and R1=10k to reduce the current?

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482 次查看
guoweisun
NXP TechSupport
NXP TechSupport

Hi

No you can't use R1=10K. In the calculation you have to keep the voltage drop of R2=200mV to keep system working normally.

482 次查看
henryy
Contributor IV

Thanks for the reply. You are right to keep the voltage drop of R2 = 200mV for working normally. But the voltage over R2 depends on the differential output, not the R1. the Two R1s only provide bias.

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482 次查看
guoweisun
NXP TechSupport
NXP TechSupport

Hi

Same current flow into R2/R1s/R1s,there is voltage drop in R2 200mV,so also there are voltage drop in R1s.

If R1s value is large the voltage drop of R2 can't reach 200mV.

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