CMU ISR

[Amr_Awny]

In CMU0, CMU3, CMU4 

the ISR of each fire 0x02, FLLI 

What are the values should be written in their division register in order to clear the ISR FLLI bit ?

CMU0

=160Mhz*16*4/16Mhz =640

LFREF = 640*0.95 = 608 --> 0x260

HFREF = 800*1.05 = 672 --> 0x2A0

MC_CGM_AC0_DC0=0x80010000

CMU3

=80Mhz*16*4/16Mhz =320

LFREF = 320*0.95 = 304 --> 0x130

HFREF = 320*1.05 = 336 --> 0x150

MC_CGM_AC0_DC2 = 0x80000000

CMU4

=80Mhz*16*4/16Mhz =320

LFREF = 320*0.95 = 304 --> 0x130

HFREF = 320*1.05 = 336 --> 0x150

MC_CGM_AC1_DC1= 0x80000000

[PetrS · Accepted solution]

Hi,

be sure clock selector MC_CGM_ACn_SC is selecting right clock, I assume PLL0 configured for 160Mhz. Or what is your selections?
Then use divider to be consistent with your calculation and clock source selected.

BR, Petr