Is fADCK (ADC conversion clock frequency) referring to the ADC clock source before it is being divided down? I'm assuming its after. But if so, doesn't the "Typical conversion time" example in 23.5.4.6.2 not meet the minimum since 8 MHz/8 = 1 MHz?

cancel
Showing results for 
Show  only  | Search instead for 
Did you mean: 

Is fADCK (ADC conversion clock frequency) referring to the ADC clock source before it is being divided down? I'm assuming its after. But if so, doesn't the "Typical conversion time" example in 23.5.4.6.2 not meet the minimum since 8 MHz/8 = 1 MHz?

1,057 Views
aarond1
Contributor I

Document Number: KL17P64M48SF6RM

16 bit SE output mode

0 Kudos
Reply
3 Replies

774 Views
EdgarLomeli
NXP Employee
NXP Employee

Hello Aaron.

ADCK signal is taken after the clock divider module as shown below:

ADCK signal.PNG

The complete block diagram is in 23.2.2

I think the example 23.5.4.6.2 it's wrong, the total conversion time it's:

ConversionTime = SFCAdder+AverageNum(BCT+LSTAdder+HSCAdder)

ConversionTime = (3ADCK+5BusK)+32(34ADCK+20ADCK)

ConversionTime = (3/1MHz +5/8MHz)+32(54/1MHz)

ConversionTime =1.731ms

Regards.

0 Kudos
Reply

774 Views
aarond1
Contributor I

But doesn't 1 MHz not meet the minimum operating condition for a 16 bit mode conversion as you can see from Table 27 in the datasheet?

pastedImage_1.png

0 Kudos
Reply

774 Views
EdgarLomeli
NXP Employee
NXP Employee

Hi Aaron. 

Unfortunately seems 23.5.4.6.2 example it's only for explanation purpose and does not considerate real operating conditions for the module. If you followed 23.5.4.6.2 configuration, an unexpected behavior would happen. 

Regards. 

0 Kudos
Reply