No source available for "0x48082010 (0x48082010)() " what does it mean?

[Futte]

when i debug my project it run into a while (1) for undefined interrupts

one of the other thread says No source available for "0x48082010 (0x48082010)() " and another says No source available for "0xFFFFFF7A (0xFFFFFF7A)() "

So my question is how can i see from the debugger which interrupt is undefined?

i use CW V10.2 and a MCU

[BlackNight]

Hello,

are you using Processor Expert?

Then you can assign an interrupt stub for every interrupt vector.

See the screenshot in http://mcuoneclipse.wordpress.com/2012/02/20/oh-my-an-interrupt/

Hope this helps,

BK

[Futte]

I am not using Processor Expert,

is there any other way to solve this or do i need to use Processor Expert?

I am a bit new to codewarrior, so i haven't heard of Processor Expert.

[BlackNight · Accepted solution]

Hello,

yes, this can be done without Processor Expert. I assume you have a vector table, maybe something like this (example for ARM/Kinetis below, but similar things apply for other architectures):

/* The Interrupt Vector Table */
void (* const InterruptVector[])() __attribute__ ((section(".vectortable"))) = {
    /* Processor exceptions */
    (void(*)(void)) &_estack,
    __thumb_startup,
    NMI_Handler,
...

    /* Interrupts */
    Default_Handler,
    Default_Handler,
    Default_Handler,

....

};

void Default_Handler(void)
{
    __asm("bkpt");
}

The idea is instead to use Default_Handler() for all the not used vectors, to use an own handler for each entry instead.

For this add one handler for each interrupt, e.g.

void Handler16(void) {    __asm("bkpt");}

void Handler17(void) {    __asm("bkpt");}

void Handler18(void) {    __asm("bkpt");}

and then use them instead of the Default_Handler() in your vector table.

That way you will know easily which interrupt fired.

Hope this helps,

BK